Calculate the volume of mercury with a density of 14.6 g/mL and a mass of 1.00 g. Please include a numeric value only with signi
ficant figures.
1 answer:
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Answer:
The heat produced is -15,1kJ
Explanation:
For the reaction:
2SO₂+O₂ → 2SO₃
The enthalpy of reaction is:
ΔHr = 2ΔHf SO₃ - 2ΔHf SO₂
As ΔHf SO₃ = -395,7kJ and ΔHf SO₂ = -296,8kJ
<em>ΔHr = -197,8kJ</em>
Using n=PV/RT, the moles of reaction are:
= <em>0,153 moles of reaction</em>
As 2 moles of reaction produce -197,8kJ of heat, 0,153moles produce:
0,153mol× = <em>-15,1kJ</em>
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Answer:
Explanation:
Hello!
In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:
We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:
In such a way, by using the NIST database, we find that:
Thus, we plug in the enthalpies of formation to obtain:
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Answer:
<h2>Density = 0.2 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
<h3>From the question the points are
mass = 6.8 g
volume = 34 mL
Substitute the values into the above formula and solve
That's
<h3>We have the final answer as
<h3>Density = 0.2 g/mL</h3>Hope this helps you