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3 years ago

11

Can someone please help me I need it quick please . Just need the answer please

1 answer:

Triss [41]3 years ago

8 0

Answer:

198 km

Step-by-step explanation:

81/9=9

9*22=198

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Find all -values that satisfy the equation sin () − 4()cos () = 0 , 0 ≤ ≤ 4

Readme [11.4K]

Answer:

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3 years ago

Using the fixed-time period inventory model, and given an average daily demand of 200 units, 4 days between inventory reviews, 5

KATRIN_1 [288]

Answer:

Correct option: B. About 1,686.

Step-by-step explanation:

The formula to compute the order quantity (Q) is:

$Q=(q_{d}\times (I+L))+(z\times\sigma_{I+L})-I_{n}$

Here

$q_{d}=average\ daily\ semand=200\\I = Inventory\ review\ time=4\\L=lead\ time=5\\\sigma_{I+L}=standard\ deviation\ over\ the\ review\ and\ lead\ time=3\\I_{n}=number\ of\ units\ of\ inventory\ on\ hand=120$

Compute the order quantity as follows:

$Q=(q_{d}\times (I+L))+(z\times\sigma_{I+L})-I_{n}\\=(200\times(4+5))+(1.96\times 3)-120\\=1800+5.88-120\\=1685.88\\\approx1686$

Thus, the order quantity was about 1,686.

5 0

3 years ago

2x + 22 4x – 2 3x + 3<br><br>find x

Vladimir79 [104]

Answer:

?Incomplete question!!

By what means these algebraic expressions are related?

5 0

3 years ago

Read 2 more answers

Please help! "Indicate the equation of the given line in standard form. The line containing the midpoints of the legs of right t

julsineya [31]

Nice. We're not really told which is the right angle. We can tell from the squared distances:

$AB^2=(1 - -5)^2 + (1-5)^2=6^2+4^2=52$

$BC^2=(3-1)^2+(4-1)^2=2^2+3^2=13$

$AC^2=(3- -5)^2+(4 -5)^2=8^2+1^2=65$

We see $AC^2=AB^2+BC^2$ so B is the right angle.

That was preliminary and probably indicated in an associated figure.

Now we want the line through the midpoint of the legs, AB and BC, in standard form.

The midpoint of AB is the average of the coordinates of A and B:

$\left( \dfrac{-5 +1}{2}, \dfrac{5+1}{2} \right) = (-2,3)$

The midpoint of BC is

$\left( \dfrac{1 + 3}{2}, \dfrac{1 + 4}{2} \right) = ( 2, \frac 5 2)$

The line through those points is

$(y - 3)(2 - -2)=(x - -2)(\frac 5 2 - 3)$

$4y - 12 = (x+2)(- \frac 1 2)$

$8y - 24 = -x -2$

$x + 8y = 22$

That's the answer. Let's check it.

Midpoint of AB is (-2,3), -2 + 8(3)=22 good.

Midpoint of BC is (2,5/2), 2+8(5/2)=22 good.

$\textrm{Answer: } x + 8y = 22$

4 0

4 years ago

Temka [501]

A standard line equation takes the form of y=mx+b

m= the slope so we see that 2 is next to x in your example

A) Slope = 2

Perpendicular lines will have the negative reciprocal of the original equation's slope

2 -> - $\frac{1}{2}$

B) $y=-\frac{1}{2} x+3$

5 0

3 years ago

Read 2 more answers