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3 years ago

Cos(x)= 40/41 and x lies in Q4. Find sin(x)

Mathematics

2 answers:

V125BC [204]3 years ago

5 0

Answer:

sinx =-9/41

Step-by-step explanation:

cos x= adjacent/hypotenuse = 40/41

sin x = opposite/ hypotenuse = x/41

how do we find o? pythagorean theorem

o²=41² -40²

0= + or - 9

Now is 9 negative or positive?

well since the graph is in quadrant 4, according to CAST Rule, Sin will always be negative

therefore o =-9

sinx = -9/41

notka56 [123]3 years ago

4 0

Step-by-step explanation:

$\sin(x) = \sqrt{1 - {cos}^{2}x }$

$\sin(x ) = \sqrt{1 - { (\frac{40}{41} )}^{2} }$

$\sin(x) = \sqrt{ \frac{1681 - 1600}{1681} } = \sqrt{ \frac{81}{1681} }$

sin(x)=±9/41

As x lies in Quadrant 4 , sin(x) = -9/41

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3 years ago

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

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3 years ago

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Answer:

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3 years ago

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Answer:

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2 years ago

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