The height of broken part of tree from ground is 5.569m.
Justification:
Let BD is a tree of height 12 m.
<u>Suppose it got bent at a point C and let the part CD take the position CA, meeting the ground at A</u>.
i.e., CD = AC = h m
<u>Broken part makes 60° angle from ground</u>
So, ∠BAC = 60°
<u>Now, height of remaining part of tree</u> = (12 – h)m.
In right angled ∆ABC,
sin 60° = BC/AC
⇒ √3/2 = (12 - h)/h
⇒ √3h = 2(12 – h)
⇒ √3h = 24 – 2h
⇒ √3h + 2h = 24
⇒ h(√3 + 2) = 24
⇒ h(1.732 + 2) = 24
⇒ h(3.732) = 24
⇒ h = 24/3.732 = 6.4308 m
<u>Hence, height of broken tree from ground</u>
⇒ BC = 12 – h
⇒ 12 – 6.4308 = 5.569m
<u>Hence, tree is broken 5.569 m from ground</u>.
<u>Note</u>: See attached picture.
Answer:
1/15 each
Step-by-step explanation:
1/5 of chocolate is separated into 3
1/5 divided by 3 = 1/5 x 1/3 = 1/15 of the whole bar
Answer:


Step-by-step explanation:
The master chief has three and a half cookies i.e.
numbers of cookies.
Again the arbiter has five and three quarters of a cookie i.e.
number of cookies.
Therefore, in total there are
numbers of cookies.
If we divide the total number of cookies in to equal parts and distribute to then then each of them will get
numbers of cookies. (Answer)
Let's simplify step-by-step.
3y-6+7y-4y
=3y+ -6+7y+ -4
Combine Like Terms.
=3y+ -6 +7y+ -4y
=6y+ -6
Answer:
6y-6