6 can only go into 6 once
Answer:
x•(2xy-3z)
Step-by-step explanation:
2x²y -3xz== x(2xy-3z)
Answer:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Step-by-step explanation:
Answer:
<em>C. y = 3x + 13.</em>
Step-by-step explanation:
The point slope form of a line is
y - y1 = m(x - x1) where m = the slope, and (x1, y1) is a point on the line.
So, substituting:
y - 1 = 3(x - -4)
y - 1 = 3(x + 4)
y = 3x + 12 + 1
y = 3x + 13.
The question is impossible to answer. as we do not have the image of the polygon
