Question

Find the value of x in the triangle shown below. 1 4 Choose 1 answer:

Answer 1

Answer:

x = $\sqrt{17}$

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² = 4² + 1² = 16 + 1 = 17 ( take square root of both sides )

x = $\sqrt{17}$

Answer 2

Answer:

x = 4.12

Step-by-step explanation:

Remark

Use the Pythagarian Theorem a^ + b^2 = c^2

a = 1

b = 4

c = ?

Solution

1^2 + 4^2 = c^2         Expand

1 + 16 = c^2               Combine

c^2 = 17                     Take the square root of both sides

sqrt(c^2) = sqrt(17)

c = 4.12                      Answer