Answer:
The second option, 3x^2(x+3)(4x+1)
Step-by-step explanation:
Factor out the common term, which is 3x^2
This then becomes 3x^2(4x^2+13x+3)
Factor the inside term and it becomes
(3x^2)(x+3)(4x+1)
The of the first multiples of 21 is 21, 42, 63, 84, 105
Am not quite sure but it’s 17
Hope this helped
Total circles needed = 32 × 4 = 128
papers needed to have 128 circles = 128 / 6 = 21.3 rounded up 22 because paper is whole number.
