Answer:
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Step-by-step explanation:
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Answer:
x = 1, y = 3
Step-by-step explanation:
Given:
- 2x + 3y + 4 = 15 ⇒ 2x + 3y = 11
Now let's check the pairs of x and y:
<u>x = 6, y = 3</u>
- 2x + 3y = 2*6 + 3*3 = 12 + 6 = 18 ≠ 11
- incorrect
<u>x = 3, y = 5</u>
- 2x + 3y = 2*3 + 3*5 = 6 + 15 = 21 ≠ 11
- incorrect
<u>x = 6, y = 4</u>
- 2x + 3y = 2*6 + 3*4 = 12 + 12 = 24 ≠ 11
- incorrect
<u>x = 1 , y = 3</u>
- 2x + 3y = 2*1 + 3*3 = 2 + 9 = 11
- correct
Answer:
y=3/2x+5
The slope is 3/2 and the y-intercept is 5
Step-by-step explanation:
Solving for y will give us the slope and y-intercept
Isolate y
2y/2=10+3x/2
y=5+3/2x
The slope is 3/2 and the y-intercept is 5
Graph it by graphing (0,5) and using the slope (up 3 over 2) to put other points
Multiply -2 and x, and you’ll have -2x. Then multiply -2 and 5, and you’ll have -10. Therefore, -2x-10=4, but we’re not done yet. We need to get x by itself, so what we’re gonna have to do is add 10 to both sides. Now you’ll have -2x=14, and when you divide both sides by -2, you’ll have x=-7 which will be your answer
Answer:
See Explanation
Step-by-step explanation:
<em>The question is incomplete as what is required of the question is not stated.</em>
<em>However, since the question is only limited to distance, a likely question could be to calculate the distance from Bayville to Colleyville.</em>
Represent the distance from Atlanta to Colleyville with AC
Represent the distance from Atlanta to Bayville with AB
Represent the distance from Bayville to Colleyville with BC
So, we have that:
![AC = 25.5\ miles](https://tex.z-dn.net/?f=AC%20%3D%2025.5%5C%20miles)
![AB = 10\frac{2}{3}\ miles](https://tex.z-dn.net/?f=AB%20%3D%2010%5Cfrac%7B2%7D%7B3%7D%5C%20miles)
The relationship between AB, AC and BC is:
![AC = AB + BC](https://tex.z-dn.net/?f=AC%20%3D%20AB%20%2B%20BC)
Make BC the subject of formula:
![BC = AC - AB](https://tex.z-dn.net/?f=BC%20%3D%20AC%20-%20AB)
![BC = 25.5 - 10\frac{2}{3}](https://tex.z-dn.net/?f=BC%20%3D%2025.5%20-%2010%5Cfrac%7B2%7D%7B3%7D)
Convert fraction to decimal
![BC = 25.5 - 10.7](https://tex.z-dn.net/?f=BC%20%3D%2025.5%20-%2010.7)
![BC = 14.8](https://tex.z-dn.net/?f=BC%20%3D%2014.8)
<em>Hence, the distance from Bayville to Colleyville is 14.8 miles</em>