3/4 × 3 2/3 in simpliest form

1 answer:

3 0

$\frac{3}{4} \times 2\frac{2}{3} \\ \\ \frac{3}{4} \times \frac{3 \times 3 + 2}{3} \\ \\ \frac{3}{4} \times \frac{11}{3} \\ \\ \frac{3 \times 11}{4 \times 3} \\ \\ \frac{33}{12} \\ \\ \frac{11}{4} \\ \\ 2 \frac{3}{4} \\ \\$

The final result is: 2 3/4 or 2.75.

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Given the function f(x)=6x-11, find f(-1/3).

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Answer:

-13

Step-by-step explanation:

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Solving and graphing systems of equations

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Hey Jackson!

-4x + 3y = 3
y = 2x + 1

Ok so what we need to do is solving y= 2x + 1 for y.

So let's start by using the substitution method :)

Substitute 2x + 1 for y in -4x + 3y = 3

-4x+ 3y = 3

-4x + 3(2x + 1) = 3

-4x + (3)(2x) + (3)(1) = 3

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Subtract 3 on both sides

2x + 3 - 3 = 3 - 3

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x = 0/2

x = 0

So now since we find the number for x, we gonna use it to help us find the value for y.

To find y, we need to substitute 0 for x in y = 2x + 1

y = 2x + 1

y = 2(0) + 1

y = 0 + 1

y = 1

Thus,

The answer is: y = 1 and x = 0

How to graph?

You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1

I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)

Let me know if you have any questions. As always, it is my pleasure to help students like you!

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What are the solutions of this quadratic equation?X2 - 10x= -34A.r=-8, -2B.r= 5 + 3iC.r=-5 + 3iD.r=-5 + 159

ololo11 [35]

The given equation is-

$x^2-10x=-34$

First, we move the independent term to the other side.

$x^2-10x+34=0$

Now, we have to use the quadratic equation to find the solutions.-

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where, a = 1, b = -10, and c = 34.

Replacing these values in the formula, we have.

$\begin{gathered} x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(1)(34)}}{2(1)} \\ x_{1,2}=\frac{10\pm\sqrt[]{100-136}}{2}=\frac{10\pm\sqrt[]{-36}}{2} \end{gathered}$

But, there's no square root of -36 because it's a negative. To solve this issue, we use complex numbers that way, we would have solutions.

$x_{1,2}=\frac{10\pm\sqrt[]{36}i}{2}=\frac{10\pm6i}{2}=5\pm3i$ <h2>Therefore, the solutions are</h2> $\begin{gathered} x_1=5+3i \\ x_2=5-3i \end{gathered}$ The right answer is B.