Let
L--------> the length of the rectangle
y------> the width of the rectangle
x------> the perimeter of the rectangle
we know that
The perimeter of the rectangle is equal to
In this problem we have
For a width
Find the value of the perimeter
so
therefore
the answer is the option A
No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y. .
Answer:
1/4
Step-by-step explanation:
The chance of it landing heads up once would be 1/2
The chance of it landing heads up twice would be 1/4
The chance of it landing heads up three times would be 1/8
The chance of it landing heads up four times would be 1/16
See the pattern?
Pattern: <em><u>Divide the denominator by 2.</u></em>
<h2>
<em>Please give brainliest!!! :) </em></h2>
Answer:
both are mathematical sentances, what you do to one side you must do to the other, goal is to isolate variable
Step-by-step explanation:
x = 
isolate 5x by adding c to both sides of the equation
5x = k + c ( divide both sides by 5 )
x = 
Answer:
fg(-2)=f(5×-2+4)=f(-6)=8-10×-6=8+60=68