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Afina-wow [57]
3 years ago
12

‼️‼️‼️PLEASE HELP ‼️‼️ I NEED HELP ASAP PLEASE ‼️‼️‼️‼️

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

C. g(x)=1/3x^2

Step-by-step explanation:

let g(x)= ax^2

It bases through the point (3,3) × -x 3= a×3^2

-x 3= a×9 -x

a= 3/9=1/3

g(x)=1/3x^2

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Evaluate the expression x + 8/27. Evaluate the expression for x=8/9
diamong [38]

Answer:

32/27

Step-by-step explanation:

Evaluate for x=

8 /9  + 8 /27

8 /9  + 8 /27

=32/27

(Decimal: 1.185185)

6 0
3 years ago
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A family pass to the amusement park costs $54 Using the Distributive Property,write an expression that can be used to fine the c
snow_lady [41]
X represents the amount of children's tickets
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3 years ago
What is 1.2 liters - 200 milliliters
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8 0
4 years ago
3.<br> a. Domain<br> b. Range<br> c. Function?
77julia77 [94]

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Step-by-step explanation:

5 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

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(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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