Answer:
The dimensions of rectangular fence are 14 feet and 20 feet.
Step-by-step explanation:
We are given the following in the question:
Length of rectangular fence = 14 feet
Width of fence = (14+x) feet
Area of rectangular field = 280 square feet
Area of rectangular field =

Putting the values, we get,

Thus, the dimensions of rectangular fence are 14 feet and 20 feet.
Consider, pls, the suggested option (see the attachment).
Answer: 2/6 or 1/3
Step-by-step explanation: First you want to change the two fractions to improper fractions, so 2 1/6 will become 13/6 and 1 5/6 will become 11/6.
Using those improper fractions, you subtract the numerators since the denominators are the same, so 13 - 11 is 2 for the numberator.
2/6 can be simplified into 1/3 by dividing the numerator and denominator by 2.
3: 18
4: 17
5: 561
6: 17
7: 23
:)
Answer:
L = 25.959 inches
Step-by-step explanation:
Volume of first cube = 375 inch³
Volume of second cube = 648 inch³
Volume of third cube = 1029 inch³
We need to find the length of the stack of the cube shaped block.
We know that,
The volume of a cube = a³ (a is side of a cube)
![a_1=\sqrt[3]{375} \\\\=7.211\ \text{inches}](https://tex.z-dn.net/?f=a_1%3D%5Csqrt%5B3%5D%7B375%7D%20%5C%5C%5C%5C%3D7.211%5C%20%5Ctext%7Binches%7D)
![a_2=\sqrt[3]{648 } \\\\=8.653\ \text{inches}](https://tex.z-dn.net/?f=a_2%3D%5Csqrt%5B3%5D%7B648%20%7D%20%5C%5C%5C%5C%3D8.653%5C%20%5Ctext%7Binches%7D)
![a_3=\sqrt[3]{1029} \\\\=10.095\ \text{inches}](https://tex.z-dn.net/?f=a_3%3D%5Csqrt%5B3%5D%7B1029%7D%20%20%5C%5C%5C%5C%3D10.095%5C%20%5Ctext%7Binches%7D)
Hence, the total length of the stack is :
L = 7.211 + 8.653 + 10.095
= 25.959 inches
Hence, this is the required solution.