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kobusy [5.1K]
3 years ago
6

An unopened cereal box contains `15/28` cubic foot of cereal. If the box is full, and the length and height of the box are `5/7`

and `1(1)/(2)` feet, respectively, what is the width of the box?
Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

1/2ft

Step-by-step explanation:

15/28=(5/7)(1 1/2)(w)

15/28=(5/7)(3/2)w

15/28=(15/14)w

(15/28)/(15/14)=w

(15/28)*(14/15)=w

w=14/28

w=1/2 ft

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it is scalene type of triangle because no sides are equal

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Write the linear equation in slope-intercept from the information given.
alexandr1967 [171]

Answer:

B)  y = -3x+2

Step-by-step explanation:

plug (2,-4) and -3 into y = mx + b to find 'b'

-4 = -3(2) + b

b = -4+6 = 2

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The line plot shows the measurement of liquids in eight identical beakers. If you wanted to put the same amount of liquid in eac
Lemur [1.5K]
C 7/8

With the graph, you add the values of the X's together and find the mean (divide by 8)

(0.25+0.5+0.5+0.5+1+1+1.5+1.75)/8
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7 0
3 years ago
Read 2 more answers
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
2 years ago
Please help <br><br> It’s due tonight
Natalija [7]

Answer: 18 units long

Step-by-step explanation:

In the diagram, it looks like line segment AW is 6 units long and WB is 12 units long. Because of parts-whole postulate (the whole is equal to the sum of its parts), you can add AW and WB's lengths together. 6 + 12 = 18, so the length of line segment AB is 18 units long.

5 0
3 years ago
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