Ask question

Ask question

All categories

3 years ago

6

An unopened cereal box contains `15/28` cubic foot of cereal. If the box is full, and the length and height of the box are `5/7`

and `1(1)/(2)` feet, respectively, what is the width of the box?

1 answer:

VikaD [51]3 years ago

4 0

Answer:

1/2ft

Step-by-step explanation:

15/28=(5/7)(1 1/2)(w)

15/28=(5/7)(3/2)w

15/28=(15/14)w

(15/28)/(15/14)=w

(15/28)*(14/15)=w

w=14/28

w=1/2 ft

You might be interested in

3-4 what is the answer I am dumb plz helq

Anika [276]

Answer:

Its -1. Do not call yourself dumb, though, negatives are the easiest subject

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of <em>y</em> as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |<em>x </em>| ≤ 605.

⇒ -605 ≤ <em>x</em> ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0

3 years ago

Please help me Asap!! I don't have much time to answer this. Will give brainliest!<br> NO LINKS!!

Advocard [28]

Answer:

3/5

Step-by-step explanation:

<u>Number of those drive to school:</u>

2 + 13 + 25 = 40

<u>Number of those don't drive:</u>

100 - 40 = 60

<u>Probability:</u>

P(Drive to school ' ) = 60/100 = 3/5

5 0

2 years ago

What is 13x= 2x+26-12.5?

Ulleksa [173]

The answer would be 6, 0.5

5 0

3 years ago

Read 2 more answers

Which scenario does not represent exponential growth?

storchak [24]

Answer:

I believe the correct answer is - The value of a bank account with quarterly compounded interest after 6 years.

I'm not sure if this is 100% correct but hope it helps.

4 0

2 years ago