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Kisachek [45]
4 years ago
10

Please give me the correct answer now

Mathematics
1 answer:
Kazeer [188]4 years ago
6 0

Answer:

<h2>x = 15.6</h2>

Step-by-step explanation:

In order to find x we use the cosine rule, since we have all two sides and an angle

So we have

x² = ZX ² + XY² - 2(ZX)(XY) cos X

From the question

ZX = 13

XY = 8

X = 93°

Substituting the values into the expression we have

x² = 13² + 8² - 2(13)(8)cos 93

x² = 169 + 64 - 208 cos 93

x² = 233 - 208 cos 93

x² = 243.885

Find square root of both sides

x = 15.616817

We have the final answer as

<h3>x = 15.6 to the nearest tenth</h3>

Hope this helps you

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What is the mean for the data set? {79,42,86,103,79,111}
kozerog [31]

Answer:

≈83.33

Step-by-step explanation:

Mean is the average

so

Mean = [79+42+86+103+79+111] / 6

= 500/6

≈ 83.33

3 0
4 years ago
Read 2 more answers
Let f(x) = 1850(0.96)^x<br><br> b) Solve the equation f(x+1) = f(x) -25
Anton [14]

Answer:

(a) -69.59 . . . . the approximate slope of the curve at x=2

(b) 26.583 . . . . the value of x where the slope of f(x) is about -25.

Step-by-step explanation:

(a) The slope of a function <em>f </em>over the interval [x, x+h] is given by ...

... slope = (f(x+h) -f(x))/h

The problem statement asks for the value of ...

... (f(2.01) -f(2))/0.01

Matching this expression to the pattern above, we find x = 2, h = 0.01. An appropriate interpretation of the expression is that it gives the approximate slope of f(x) near x=2.

The value of that slope is about ...

... (f(2.01) -f(2))/0.01 ≈ 1850·(0.92122386 -0.9216)/.01 ≈ -69.5857

(b) f(x+1) = 1850·0.96^(x+1) = 0.96·f(x)

Then the equation becomes ...

... 0.96·f(x) = f(x) -25

... 25 = 0.04·f(x) . . . . . . . . add 25-0.96·f(x)

... 625 = f(x) . . . . . . . . . . . multiply by 25

... 625 = 1850·0.96^x . . . substitute definition of f(x)

... 625/1850 = 0.96^x . . . divide by the coefficient of the exponential term

... log(625/1850) = x·log(0.96) . . . . take logs

... x = log(625/1850)/log(0.96) ≈ -0.471292/-0.0177288

... x ≈ 26.583

If you rearrange the equation to ...

... f(x+1) -f(x) = -25

Comparing this to the equation for slope, above, it looks a lot like we're trying to find the interval [x, x+1] over which the average slope is -25.

6 0
4 years ago
Chapman Inc. doubles the amount of its assets from the beginning to the end of the year. Liabilities at the end of the year amou
Sveta_85 [38]

The amount of Chapman's assets at the beginning of the year  is $40,000

What is accounting equation?

The accounting equation stated that the total assets of a company is the same as its owner's equity plus total labilities

Total assets=owner's equity+liabilities

Total assets at the end of the year=2*assets at the beginning

let us assume beginning assets were x

Total assets at the end of the year=2x

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x=$80,000/2

x=assets at the beginning of the year=$40,000

Find out more about accounting equation on: brainly.com/question/14523202

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8 0
2 years ago
Please help me without using a link.Thank you!
katovenus [111]

Answer:

O

Step-by-step explanation:

8 0
3 years ago
Which equation represents the hyperbola shown in the graph? A. x-3^2/64-y-1^2/36=1 B. x+3^2/64-y+1^2/36=1 C. y+1^2/64 - x+3^2/36
Leokris [45]

Answer:

C. (y + 3)²/64 - (x + 1)²/36 = 1

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo

My answer:

From the photo, the given information is:

  • The vertex : (−1, 5).
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As we know, the hyperbola has general equation for it is:

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where h and k are the coordinate for the center (h, k) and we  only needed the center of the hyperbola to find our answer.

In this situation, we have:

\frac{(y-(-3))^{2} }{a^{2}}-\frac{(x-(-1))^{2} }{b^{2}}=1\\\frac{(y+3)^{2} }{a^{2}}-\frac{(x+1)^{2} }{b^{2}}=1

Hence, we choose C.

Hope it will find you well.

4 0
4 years ago
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