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4 years ago

What is a rotation in geometry?

1 answer:

6 0

Rotation is transformation that turns a figure clockwise or counterclockwise. The pre-image and image are congruent in a rotation

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In the triangle shown below TB, EC and are MEDIANS; TB = 6x - 15 and DB = 5 5. Solve for x

nydimaria [60]

Answer:

I am not sure on this one, sorry :(

Step-by-step explanation:

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3 years ago

When (3,-2) is reflected across the x-axis the resulting image point is:

FromTheMoon [43]

Answer:

(3,2)

Step-by-step explanation:

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3 years ago

Given: a = 8, b = 6, C = 60° Find angle A

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3 years ago

Write an equation (y=mx+b) through the points: (3,-1) and (8,9)

Advocard [28]

Answer:

y=2x-7

Step-by-step explanation:

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3 years ago

3. Suppose the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 custo

stich3 [128]

Answer:

The probability that the average number of customers in the sample is between 290 and 310 is 0.61922.

Step-by-step explanation:

We are given that the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 customers.

A random sample of 50 business days was selected.

Let $\bar X$ = sample average number of customers

The z-score probability distribution for sample average is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population average = 301 customers

$\sigma$ = population standard deviation = 80 customers

n = sample of business days = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability the average number of customers in the sample is between 290 and 310 is given by = P(290 < $\bar X$ < 310) = P( $\bar X$ < 310) - P( $\bar X$ $\leq$ 290)

P( $\bar X$ < 310) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{310-301}{\frac{80}{\sqrt{50} } }$ ) = P(Z < 0.79) = 0.78524

P( $\bar X$ $\leq$ 290) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{290-301}{\frac{80}{\sqrt{50} } }$ ) = P(Z $\leq$ -0.97) = 1 - P(Z < 0.97)

= 1 - 0.83398 = 0.16602

{Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.79 and x = 0.97 in the z table which has an area of 0.78524 and 0.83398 respectively.}

Therefore, P(290 < $\bar X$ < 310) = 0.78524 - 0.16602 = 0.61922

Hence, the probability that the average number of customers in the sample is between 290 and 310 is 0.61922.

4 0

3 years ago