<em>4</em><em>0</em><em>+</em><em>40</em><em>+</em><em>40</em>
<em>6.80</em><em>÷</em><em>2</em>
<em>and</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>do</em><em> </em><em>this</em><em> </em>
<em>you</em><em> </em><em>will</em><em> </em><em>end</em><em> </em><em>up</em><em> </em>
<em>getting</em><em> </em><em>your</em><em> </em><em>answers</em><em> </em>
Answer is given below
Step-by-step explanation:
given data
average length of all 1015 fishes = 98.06 mm
randomly selects 50 fishes average length = 101.04 mm
solution
- When we get here, we mean to measure, so here we measure a fish in a square lake.
- And the variable means that a fish varies from fish to fish, so the length of the fish in the squares
- parameter mean that all individuals in the population so the parameter is average length of all 1015 fish in square lake
- statics is selct of individual in sample so statistic is average length of random sected so fish in square lake
Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am
Answer:
The first one : decay
The second one : growth
When the argument of the exponential expression is bigger that 1 then it represents a growth
When it's less than 1 and above 0 then it's a decay
Wouldn't you be 17 cause plus one is 2000 and then one plus 16 equals 17
