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kvasek [131]
3 years ago
7

Names two planes that do not intersect

Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0

Answer:

parellel planes do not intersect

non-coplanar also dont

Luden [163]3 years ago
8 0

Answer:

y=x+0z

y=x+0z-5

Step-by-step explanation:

By far the easiest way to do it is using linear equations

we know that

y=x and

y=x-5

don't ever touch

so we can graph it on 3D and we get

and like the lines the planes don't touch

You might be interested in
If angle 2 has a measurement of (x+4) and angle 3 has a measurement of 3x what does x equal?
deff fn [24]

Answer:

x = 44 degrees.

Step-by-step explanation:

Hi!

Since m<2 and m<3 equal 180 degrees (sum of flat line), we can form an equation

(x+4) + (3x) = 180

x + 4 + 3x = 180

4x + 4 = 180

4x = 176

Divide by 4 on both sides

x = 44 degrees

Let me know if you have any questions

6 0
3 years ago
Write the equation of the line that includes the point (1,5) and has a slope of 3 in standard form.
Ymorist [56]

Answer:

-3x + y = 2

Step-by-step explanation:

The slope is 3. So the coefficient of x is 3.

when x = 1, y = 5.

So 3*1 + c = 5

So c is 2.

So y = 3x + 2

Therefore, taking 3x to the LHS, we get,

-3x + y = 2

Hope it helps ;)

7 0
3 years ago
Read 2 more answers
5.
nikitadnepr [17]

Answer:

i am not so sure but I think its 10x = 33

3 0
3 years ago
If f(x) = 2 + 1, then f(3) =
Agata [3.3K]
F(3) is 3 since the equation of the line is f(x)=3
4 0
2 years ago
Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
4 years ago
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