Answer:
- pitcher: $48 million
- shortstop: $8 million
Step-by-step explanation:
The ratio of salaries can be written as ...
short : pitcher = 1 : 6
Then the fraction of the total that the shortstop received is ...
short : total = 1 : (1+6) = 1 : 7
The shortstop's salary was (1/7)×($56 million) = $8 million.
The pitcher's salary was 6 times that, so 6×($8 million) = $48 million.
The pitcher's salary was $48 million; the shortstop's, $8 million.
Answer:
$12,500.
Step-by-step explanation:
We have been given that a salesperson works 40 hours per week at a job where he has two options for being paid. Option A is an hourly wage of $25. Option B is a commission rate of 8% on weekly sales.
First of all we will find amount earned by salesperson with option A.
The salespersons earns $1000 through option A.
Let x be the amount of weekly sales.
8% of x should be equal to 1000 for salesman to earn the same amount with the two options.



Therefore, the salesman needs to make a weekly sales of $12,500 to earn the same amount with two options.
Answer:4x + 12 = 2 ( 2x + 6)
Step-by-step explanation:
<h2>
Answer:</h2>
![\boxed{(-\infty,-3] \ U \ [3,4] \ U \ \{-2\}}](https://tex.z-dn.net/?f=%5Cboxed%7B%28-%5Cinfty%2C-3%5D%20%5C%20U%20%5C%20%5B3%2C4%5D%20%5C%20U%20%5C%20%5C%7B-2%5C%7D%7D)
<h2>
Step-by-step explanation:</h2>
To solve this problem we need to use the Test Intervals for Polynomial. The following steps helps us to determine the intervals on which the values of a polynomial are entirely negative or entirely positive.
1. Find all real zeros of the polynomial arranging them in increasing order from smallest to largest. We call these zeros the critical numbers of the polynomial.
Before we start applying this steps, let's multiply the entire inequality by -1 changing the direction of the inequality, so the result is:

So the real zeros are:

2. Use the real zeros of the polynomial to determine its test intervals.

3. Take one representative x-value in each test interval, then evaluate the polynomial at this value. If the value of the polynomial is negative, the polynomial will have negative values for every x-value in the interval. If the value of the polynomial is positive, the polynomial will have positive values for every x-value in the interval.
<u>Polynomial values</u>
___________________

___________________
At x = -3, x = 3, and x = 4 we use brackets because the inequality includes the value at which the polynomial equals zero.
Finally, if you set
:

So
is also a solution to the system. Finally, the solution is:
![\boxed{(-\infty,-3] \ U \ [3,4] \ U \ \{-2\}}](https://tex.z-dn.net/?f=%5Cboxed%7B%28-%5Cinfty%2C-3%5D%20%5C%20U%20%5C%20%5B3%2C4%5D%20%5C%20U%20%5C%20%5C%7B-2%5C%7D%7D)