Hello!
I have all the work but I do not know how to post it on here.
The area of the figure shown is 57.
I hope it helps!
Answer:
The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.
y = a(x-h)2 + k standard form
y = 5x2 - 4 original equation
y = 5(x-0)2 - 4 re-written in standard form
h = 0 k = -4
Four (4) units up is k + 4--->-4 + 4 = 0.
Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.
Step-by-step explanation:
hope this helps
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Note
Write the number until underlined point.I did it till end
Answer:
13a+27
Step-by-step explanation:
8a+12+5a+15= 13a+27