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pychu [463]
3 years ago
14

Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 50 kg ball tra

veling at 10 m/s.
a 50 kg ball traveling at 20 m/s would have _____ kinetic energy.

a 50 kg ball traveling at 5 m/s would have _____ kinetic energy.

a 50 kg ball traveling at 10 m/s would have _____ kinetic energy.

- the same

- 2 times more

- 2 times less

- 4 times more

- 4 times less
Chemistry
2 answers:
Arada [10]3 years ago
6 0
The kinetic energy=mv^2/2
1)4 times kore
2)4times less
3)the same
Mama L [17]3 years ago
5 0

Explanation:

It is known that kinetic energy is half of mass times velocity square.

Mathematically,   K.E = \frac{1}{2}mv^{2}

where        m = mass

                  v = velocity

The kinetic energy from which we have to compare shows that mass is 50 kg and v = 10 m/s.

Therefore,      K.E = \frac{1}{2}mv^{2}

                             = \frac{1}{2}50 \times 10^{2}

                             = 2500 m/s^{2}

1).  K. E = \frac{1}{2}mv^{2}

            = \frac{1}{2}50 \times 20^{2}

            = 10000 m/s^{2}

The object has 4 times more kinetic energy compared to a 50 kg ball traveling at 10 m/s.

2). K. E = \frac{1}{2}mv^{2}

            = \frac{1}{2}50 \times 5^{2}

            = 1250 m/s^{2}

The object has 2 times less kinetic energy compared to a 50 kg ball traveling at 10 m/s.

3). K. E = \frac{1}{2}mv^{2}

            = \frac{1}{2}50 \times 10^{2}

            = 2500 m/s^{2}

The object has the same kinetic energy compared to a 50 kg ball traveling at 10 m/s.

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What is the volume of 9.5 g fluorine gas, F2, at STP?
Tju [1.3M]

Answer:

5.6L

Explanation:

At STP, the pressure and temperature of an ideal gas is

P = 1 atm

T = 273.15k

Volume =?

Mass = 9.5g

From ideal gas equation,

PV = nRT

P = pressure

V = volume

n = number of moles

R = ideal gas constant =0.082J/mol.K

T = temperature of the ideal gas

Number of moles = mass / molar mass

Molar mass of F2 = 37.99g/mol

Number of moles = mass / molar mass

Number of moles = 9.5 / 37.99

Number of moles = 0.25moles

PV = nRT

V = nRT/ P

V = (0.25 × 0.082 × 273.15) / 1

V = 5.599L = 5.6L

The volume of the gas is 5.6L

5 0
3 years ago
Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe
stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in container A = 165 mmHg

P_2 = final pressure of gas = ?

V_1 = initial volume of gas in container A= 135 mL

V_2 = final volume of gas = 135 mL + 117 mL = 252 mL

T_1 = initial temperature of gas in container A = 22.5^oC=273+22.5=295.5 K

T_2 = final temperature of gas = 12.7^oC=273+12.7=285.7K

Now put all the given values in the above equation, we get:

P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}

=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}

P_2=85.5 mmHg

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0
4 years ago
CO_2 sublimes readily at 25°C. Which properties are usually associated with a compound that undergoes this kind of change?
antoniya [11.8K]

Explanation:

Sublimation is defined as a process in which solid state of a substance directly changes into vapor or gaseous state without undergoing liquid phase.

For example, naphthalene balls show sublimation at room temperature.

As this process does not cause any change in chemical composition of a substance. Hence, it is known as a physical process.

Similarly, when CO_{2} sublimes readily at 25^{o}C. This shows change in physical state of carbon dioxide is taking place, i.e, from solid to gaseous phase.

Thus, we can conclude that when CO_{2} sublimes readily at 25^{o}C then it means physical properties are usually associated with a compound that undergoes this kind of change.

4 0
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tester [92]

the correct answer is False.

6 0
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Zigmanuir [339]
Plz specify your answer. thank u
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