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3 years ago

Many factors influence the amount of a solute which will dissolve in a solvent. True False

Chemistry

1 answer:

Nikitich [7]3 years ago

8 0

This is true there are many factors that influence the amount of a solute.

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3 years ago

A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm. The block weighs 1587 g. From thisinformation, calculate the de

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3 years ago

The two products that are formed when a solution of HNO3 and a solution of NaOH react are water and?

Naily [24]

Answer:

NaNO3

Explanation:

Hello,

In this case, the required reaction is an acid-base neutralization reaction which is said to be:

$HNO_3+NaOH\rightarrow NaNO_3+H_2O$

There, we see that the sodium displaced the hydrogen in the nitric acid to form sodium nitrate a very used salt in the industry, so, as a result of that displacement, water is formed as the secondary neutralization product. For the above mentioned, answer is NaNO3 .

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3 years ago

Read 2 more answers

Why aren't hydrogen fuel cells currently available to the public

Romashka-Z-Leto [24]

Answer:

they require more testing in real-word conditions

Explanation:

One of the biggest reasons for this very slow uptake of hydrogen vehicles is the existing infrastructure. ... The sceptics' first argument against hydrogen vehicles is that they're less efficient than EVs are. Because hydrogen doesn't occur naturally, it has to be extracted, then compressed in fuel tanks.

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3 years ago

How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine? ___ H2 + ___ Cl2 ___ HCl ΔH

True [87]

Answer:

How much energy would be produced from the reaction of 2.40 moles hydrogen with 3.95 moles chlorine?

$H_2 + Cl_2 -> 2HCl , deltaH = -554 kJ$

Explanation:

Given,

2.40 moles hydrogen reacts with 3.95 moles chlorine.

From the balanced chemical equation,

1mol. of H2 reacts with 1mol. of Cl2

then,

2.40mol. of H2 reacts with ----?mol of Cl2

$=>2.40 mol. H2 * \frac{1mol. Cl2}{1mol. H2} \\=2.40 mol. Cl2$

So, the remaining moles of Cl2 is in excess.

The limiting reagent is--- H2.

1mol. of H2 releases --- 554kJ of energy

then,

2.40mol of H2 releases ---- ?

$=>2.40mol * \frac{554kJ}{1 mol.} \\=1329.6kJ$

Answer is: deltaH =-1329.6kJ

3 0

3 years ago