Ask question

Ask question

All categories

3 years ago

12

A square rug covers 79 square feet of floor. What is the approximate length of one side of the rug? (Approximate to the nearest

hundredth foot.)
8.86 feet

8.87 feet

8.88 feet

8.89 feet

2 answers:

Strike441 [17]3 years ago

5 0

Thank you for posting your question here at brainly. Feel free to ask more questions.
<span>The best and most correct answer among the choices provided by the question is sqrt(79) or 8.89 feet.</span>
<span>
<span>Hope my answer would be a great help for you. </span> </span>

<span> </span>

egoroff_w [7]3 years ago

4 0

Answer: The correct option is (D) 8.89 feet.

Step-by-step explanation: Given that a square rug covers 79 square feet of floor.

We are to find the approximate length of one side of the rug to the nearest hundredth foot.

Let, x feet represents the length of one side of the square rug.

Then, according to the given information, we have

$x\times x=79\\\\\Rightarrow x^2=79\\\\\Rightarrow x=\pm\sqrt{79}\\\\\Rightarrow x=\pm8.888.$

Since the length of the side of the square rug can not be negative, so

x = 8.888 feet.

Rounding to the nearest hundredth foot, we get

x = 8.89 feet.

Thus the approximate length of one side of the rug is 8.89 feet.

Option (D) is correct.

You might be interested in

HELP PLEASE I need help look below for the picture and please if you can explain your answer if not that’s fine but this is a bi

Olegator [25]

Answer:

y = (3/2)x - 3

Step-by-step explanation:

Slope-Intercept Form is: y = mx + b, where m is the slope and b is the y intercept.

The slope is (3-0)/(4-2) = 3/2

The y-intercept is shown in the graph to be (0,-3).

The equation is y = (3/2)x -3

3 0

3 years ago

Read 2 more answers

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

4 0

3 years ago

Giving brainliest please help

Nezavi [6.7K]

Answer:

$(x, \: y) --->\: (x - 3, \: \: y - 5)$

7 0

2 years ago

What’s the approximate value of tan 1

goldfiish [28.3K]

Answer: tan 1 radians = 1.557, tan 1 degrees = 0.017

6 0

2 years ago

PLEASE ANSWER ASAP!<br> 2(h -3.5) = -11<br> what is h?

masya89 [10]

Answer: -2

Step-by-step explanation:

2(h -3.5) = -11 Distributive property

2h - 7 = -11. Add 7 to both sides

2h = -4. Divide both sides by 2

h = -2

3 0

3 years ago

Read 2 more answers