Answer:
Step-by-step explanation:
to solve this problem we can use the Pythagorean theorem
UT and TL are the legs, while LU is the hypotenuse
We have to find LU so we can proceed like this
x^2 + (x+1)^2 = LU^2
x^2 + x^2 + 1 + 2x = LU^2
2x^2 + 2x + 1 = LU^2
LU = +/- 
we have to take only the positive value because a length can’t be negative.
2x^2 + 2x + 1 is positive for every value of x, so the final answer is
You can take out an x
X(6x^2+5x-4)
Then factor it
X(3x+4)(2x-1)
A and d I believe..............
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
We are asked to solve for the surface area of the described figure in the problem. We can conclude that the given figure is a rectangular prism since it was being mentioned in the problem that the height is laid flat. Therefore, the formula for the surface area is SA = PH + 2B where "P" stands for the perimeter of the rectangle and "B" stands for the area of the rectangle while "H" is for the height.
Solving for P, we have it:
P = width + length + width + length
P = 10 + 5 + 10 + 5
P = 30 inches
Solving for B, we have it:
B = length * width
B = 10 * 5
B = 50 inches squared
Solving for the surface area, we have it:
SA = PH + 2B
SA = 30*7 + (2*50)
SA = 310 inches squared
The answer is 310 in2.
