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murzikaleks [220]
3 years ago
15

-y varies inversely with x. If y = 8 and k (the constant of variation) = 19, what is x?

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

Part 1) x=2.375

Part 2) y=3.3

Part 3) k=6.7

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

Part 1) y varies inversely with x. If y = 8 and k (the constant of variation) = 19, what is x?

we know that

y*x=k

substitute the given values and solve for x

8*x=19

x=19/8

x=2.375

Part 2) y varies inversely with x, and k (the constant of variation) = 23. What is the value of y when x = 7?

we know that

y*x=k

substitute the given values and solve for y

y*7=23

y=23/7

y=3.3

Part 3) y varies inversely with x. When y = 6.7, x = 1. What is the value of k, the constant of inverse variation?

we know that

y*x=k

substitute the given values and solve for k

6.7*1=k

k=6.7

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4 0
2 years ago
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Ber [7]

Answer:

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Step-by-step explanation:

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Hope this helps!

5 0
2 years ago
Let A and B be two events in a sample space S such that
klasskru [66]
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)

</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
5 0
3 years ago
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