There are fours ways to solve polynomial equations..........
Polynomial Equation Degree Example
Linear Equations 1 -3x + 1 = 4x + 5
Quadratic Equations 2 x2 – 6x + 9 = 0
Cubic Equations 3 x3 – 2x2 + 3x = -5
Quartic Equations 4 x4 – 2x2 = -4
It's really not that hard.....
x = -8
Step-by-step explanation:
Step 1: Subtract 1 from both sides
Divide both sides of the equation by -10
From the given options, the correct word that comes in the blank is variables.
Because l<span>ike terms are the terms that have the same variables with each variable raised to the same exponent.
</span>Unlike terms are the opposite of like terms, as they do not have the same variables and exponents or powers.
like terms and unlike terms are used in algebra.
Answer:
Step-by-step explanation:
Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.
Therefore, we now have two inequalities to solve for:
125-u ≤ 30
u-125≤30
For the first one, we can subtract 125 and add u to both sides, resulting in
0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.
The second one can be figured out by adding 125 to both sides, so u ≤ 155.
Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,
u ≥ 95
and
u ≤ 155
combine to be
95 ≤ u ≤ 155, or the 4th option
Answer:
Your number is (3 sqrt(2)) / sqrt(2) = 3, and is a rational number indeed. I don't know exactly how to interpret the rest of the question. If r is a positive rational number and p is some positive real number, then sqrt(r^2 p) / sqrt(p) is always rational, being equal r. Possibly your question refers to situtions in which sqrt(c) is not uniquely determined, as for c negative real number or complex non-real number. In those situations a discussion is necessary. Also, in general expressions the discussion is necesary, because the denominator must be different from 0, and so on.
Step-by-step explanation:
