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SSSSS [86.1K]
3 years ago
9

if there are 20 vakues in a data set in order from smallest to largest what is the median of the data set

Mathematics
1 answer:
Bumek [7]3 years ago
5 0
To find the median of 20 values, list the values from smallest to largest then add the 10th and 11th number then divide by 2 and you get your median.
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Solve for A<br> Exact (no rounding, no calculator needed)<br><br> 0 = A^2 + 13A + 36
marysya [2.9K]

Answer:

-4 or -9

Step-by-step explanation:

-a^2-13a-36=0

(-a-4)(a+9)=0

-a-4=0

a+9=0

a= -4, -9

3 0
2 years ago
Find the indicated area under the curve of the standard normal​ distribution; then convert it to a percentage and fill in the bl
galben [10]

Answer:

95%

Step-by-step explanation:

About 95% of the area is within two standard deviation in standard normal distribution. This can be explained by finding the probability within 2 standard deviation using standard normal distribution.

P(z1<Z<z2)=P(-2<Z<2)

P(-2<Z<2)=P(-2<Z<0)+P(0<Z<2)

P(-2<Z<2)=0.4772+0.4772

P(-2<Z<2)=0.9544

Thus, About 95% of the area is between z2 and z2

4 0
2 years ago
Is the relationship between weight and the amount of medicine linear? Explain. (2 points) help!!!!
Svetach [21]

Answer: Each age is 12 more than the last so the rate of change would be twelve. Yes it is linear, every twelve pounds is 2.5 more millimeters of dosage.

8 0
2 years ago
Read 2 more answers
Which value of x is a solution of the inequality?
avanturin [10]

Answer:

3x-3>=9=>

3x>=12=>

x>=4

5 0
2 years ago
Read 2 more answers
PLEASE HELP.
krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) DE=4\sqrt{10}\ cm

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

AE^{2}=AC^{2}+CE^{2}

substitute the values and solve for CE

14^{2}=6^{2}+CE^{2}

CE^{2}=14^{2}-6^{2}

CE^{2}=160

CE=\sqrt{160}\ cm

CE=4\sqrt{10}\ cm

remember that

CE=DE

so

DE=4\sqrt{10}\ cm

7 0
3 years ago
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