Answer:
-1/2 -i
Step-by-step explanation:
The midpoints is found by adding the real part and dividing by 2 and then the imaginary part and dividing by 2
(-2 +1)/2, (-5+3)i/2
-1/2, -2i/2
-1/2 -i
Given:
7 red candies
9 blue candies
12 pink candies
Condition:
Number of bags that has equal number of candies.
We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.
We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.
We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
D. -4
sq rt of 3x+28-8=x
add 8 to both sides
sq rt of 3x+28 = x+8
square both sides of the equation
3x + 28 = x^2 + 16x + 64
subtract x^2+16x+64 from both sides
group common terms
-13x-36-x^2=0
rearrange and put in quadratic form
x= -13 +/- sq rt of 13^2-4(1)(36) over 2(1)
subtract 169 by 144
x= -12 +/- sq rt of 25 over 2
solve for both sides
x = -13+5 over 2
=-4
x= -13-5 over 2
= -9
now plug in x
sq rt of 3(-4)+28 -8=-4
sq rt of 3(-9)+28 -8= -9
-4 = -4
but
-7 does not = -9
so -4 is the solution
(i just changed my answer)
sqrt is the square root of
v=sqrt(2(ke)/m)
Answer:
error occurred in Step 1 because 2/3 and 1/4 should have been multiplied instead of added; so answer would be x^1/6
Step-by-step explanation:
