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Semmy [17]
4 years ago
11

How would I solve for V?

ula1" title="ke = \frac{1}{2} mv^{2} " alt="ke = \frac{1}{2} mv^{2} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Shkiper50 [21]4 years ago
4 0

(i just changed my answer)

sqrt is the square root of

v=sqrt(2(ke)/m)

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Solve for x and y. -4x + 8y = -4 4x = 3y + 14
algol13
Hello!! Lets do this step by step! :) 
<span><span><span><span>−<span>4x</span></span>+<span>8y</span></span>=<span>−4</span></span>;<span><span>4x</span>=<span><span>3y</span>+14</span></span></span> <span><span><span>
<span /></span><span /></span><span /></span>To first get x:
<span><span><span><span>−<span>4x</span></span>+<span>8y</span></span>+<span>−<span>8y</span></span></span>=<span><span>−4</span>+<span>−<span>8y  </span></span></span></span>we are ganna add -8y to both sides
<span><span>−<span>4x</span></span>=<span><span>−<span>8y</span></span>−4</span></span><span><span><span>−<span>4x</span></span><span>−4</span></span>=<span><span><span>−<span>8y</span></span>−4</span><span>−4  </span></span></span>we are ganna divide both sides by -4
<span>x=<span><span>2y</span>+1</span></span>
 next just substitute <span><span>2y</span>+1</span> for x in<span><span><span> 4x</span>=<span><span>3y</span>+14</span></span>:</span><span><span>4x</span>=<span><span>3y</span>+14</span></span><span><span>4<span>(<span><span>2y</span>+1</span>)</span></span>=<span><span>3y</span>+14</span></span><span><span><span>8y</span>+4</span>=<span><span>3y</span>+14</span></span><span><span><span><span>8y</span>+4</span>+<span>−<span>3y</span></span></span>=<span><span><span>3y</span>+14</span>+<span>−<span>3y</span></span></span></span> 
we are ganna add -3y to both sides <span><span><span>5y</span>+4</span>=14</span><span><span><span><span>5y</span>+4</span>+<span>−4</span></span>=<span>14+<span>−4</span></span></span>
we are ganna add -4 to both sides <span><span>5y</span>=10</span><span><span><span>5y</span>5</span>=<span>105</span></span>
now we are ganna divide both sides by 5 <span>y=2</span>substitute 2 for y in<span><span> x=<span><span>2y</span>+1</span></span>:</span><span>x=<span><span>2y</span>+1</span></span><span>x=<span><span><span>(2)</span><span>(2)</span></span>+1</span></span><span>x=5</span>

And we get our answer!
x=5
y=2

Hope that helps! If you have any other questions or need further explanation just let me know! :)

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to (2^3)^-5 <br> a. 1/2^15 <br> b. 1/2^8 <br> c. 2^8 <br> d.2^15?
koban [17]
(2^3)^-5 = 2^(3 x -5) = 2^-15 = 1/2^15
4 0
3 years ago
At a candy store, Erika
Readme [11.4K]

Answer:

?

Step-by-step explanation:

6 0
3 years ago
How do you solve for(−5)^5(−5)^−6
Aleonysh [2.5K]

Answer:

-1/5

Step-by-step explanation:

We know that a^b * a^c = a^(b+c)

(−5)^5(−5)^−6

(-5) ^(5+-6)

(-5)^-1

We know that a^-b = 1/a^b

1/(-5)^1

1/-5

-1/5

3 0
3 years ago
50 points, basic math, about areas<br> Can somebody please give me the answers to these?
Alexeev081 [22]

Answer:

1. 70.

2. 29.

3. 442.5

4. 289.

5.  632.

Step-by-step explanation:

The key to doing these is to split the polygons into  rectangles, triangles or trapezoids as appropriate.

For example, number 1 consists of a rectangle area 8 * 8 and another of   3* 2.

So the area = 64 + 6 = 70 unit^2.

2.  The area = sum of 3 rectangles 1*1 + 4*6 + 2*2.

3. Area = 11*15 + 11*15 + 1/2*15*15

4.  Area = 18*12 + 1/2 * 6 * 15 + 1/2 * 7 * 8.

5. Area = area of 2 rectangles + area of a trapezoid.

=  18 * 24 + 4*10 + 1/2(12 + 20) * 10.

7 0
3 years ago
Read 2 more answers
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