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Semmy [17]
4 years ago
11

How would I solve for V?

ula1" title="ke = \frac{1}{2} mv^{2} " alt="ke = \frac{1}{2} mv^{2} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Shkiper50 [21]4 years ago
4 0

(i just changed my answer)

sqrt is the square root of

v=sqrt(2(ke)/m)

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3 years ago
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Fully simplify −10x3y2(9x)
lbvjy [14]

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Step-by-step explanation:

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5 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
What is 2/3 of 12348
Reil [10]
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8231.99999999
(sorry all the never ending numbers. hoped it helped :)   )
6 0
3 years ago
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zhenek [66]

Answer:

X would be x < 9

Step-by-step explanation:

You would do this equation like any other equation, but with the equal sign being greater or less than. So you would add 4 on both sides to get x < 9

8 0
3 years ago
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