<span>Answer:
Graham's law of gaseous effusion states that the rate of effusion goes by the inverse root of the gas' molar mass.
râšM = constant
Therefore for two gases the ratio rates is given by:
r1 / r2 = âš(M2 / M1)
For Cl2 and F2:
r(Cl2) / r(F2) = âš{(37.9968)/(70.906)}
= 0.732 (to 3.s.f.)</span>
Answer:
1 and 2
Trigonal planar
Tetrahedral
Trigonal Planar
Linear
Bent ( v- shape)
Explanation:
The highlighted atoms has a delocalized lone pair - 1 and 2
All sp2-hybridized carbon atoms have geometry- Trigonal planar
All sp3-hybridized carbon atoms have geometry - Tetrahedral
The nitrogen atom has geometry - Trigonal Planar
The oxygen atom of the C=O bond has geometry - Linear
and the other oxygen atom has geometry - Bent ( v- shape)
P.S - The correct question is -
Answer:
molar mass of carbon tetrafluoride (CF4) is
(12.01 × 1 ) + ( 4 × 19.00)
= 12.01 + 76
= 88.01u
= 88u
Hope this helps
Each enzyme's active site is suitable for one specific type of substrate – just like a lock that has the right shape for only one specific key. Changing the shape of the active site of an enzyme will cause its reaction to slow down until the shape has changed so much that the substrate no longer fits.
Answer:
Because oxygen is the combustion fuel and glucose is the substrate needed for synthesis of energy as ATPs during cellular respiration.Therefore Guillermo lacks enough energy as ATPs in her body cells, especially skeletal muscles cells to complete the task of ascending the s steps.
For all the mitochondrial in cells(sites of energy production) to receive needed glucose,and other metabolites needed for energy synthesis; an efficient transport system is needed, so that these materials are available immediately, in required amount. This system is called circulatory system.
And for the the supply of combustion fuel (oxygen) needed for the completion of the ATP synthesis mechanisms; respiratory systems which convey oxygen from the external environments to the circulatory system through breathing mechanisms, for distribution is needed.
Thus the doctor needs to test both the circulatory and respiratory systems.
Explanation:
