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blagie [28]
4 years ago
12

Please helppp asaappppppp

Chemistry
1 answer:
Zanzabum4 years ago
8 0

Answer:

B. s, p, d, f

Explanation:

These things are often referred to as suborbitals and you normally have s,p,d,f.

S has 1 two orbitals

P has 3 orbitals

D has 5 orbitals

F has 7 orbitals

and each orbital can house 2 electrons

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The half-life of radium-226 is 1590 years. (a) A sample of radium-226 has a mass of 50 mg. Find a formula for the mass of the sa
Maksim231197 [3]

Answer:

Explanation:

a )

m = m₀ e^{-\lambda t

m is mass after time t . original mass is m₀ , λ is disintegration constant

λ = .693 / half life

= .693 / 1590

= .0004358

m = m₀ e^{- 0.0004358 t}

b )

m = 50 x e^{-.0004358\times 500}

= 40.21 mg .

c )

40 = 50 e^{-.0004358t

.8 = e^{-.0004358t

e^{.0004358t = 1.25

.0004358 t = .22314

t = 512 years .

4 0
3 years ago
CuCl2 + NaNO3 -------> Cu(NO3)2 + NaCl
pav-90 [236]

Answer:

what

Explanation:

3 0
3 years ago
Does the absolute reference system consider a fixed reference system of reference?
Rufina [12.5K]

Answer:

The definition of an absolute reference frame would be that fixed reference frame that every observer would rest at all times in his/her state of motion.

Explanation:

6 0
2 years ago
The prefix ‘kilo-‘ means a thousand.
Blababa [14]

Answer:

0.97 kg, 1.0kg

Explanation:

As you have mentioned in the question, to convert kilo-gram to grams, this conversion is used, 1 kilogram = 1,000 grams

Initially, when one has to convert from one unit to another, there is a lot of confusion. To avoid any such, multiply and divide the number with units to which it has to be converted.

Here,

970 g = 970 g \times\frac{1 kg}{1 kg}

This makes no difference to the number.

970 g =  970 g \times\frac{1 kg}{1000 g}

As, 1 kg= 1,000 g

970 g =  \frac{970}{1000} kg

970 g = 0.97 kg

Rounding this off to the nearest tenth of a kilogram.

The tenths place is immediately to the right of the decimal point.

Here, 9 is at the tenth's place. Round the tenth's place up if the digit at hundredth's place is greater than or equal to 5. Since, 7 > 5, up the number at tenth's place.

So, answer is 1.0 kg

8 0
3 years ago
Instead of using ratios for back titrations we can also use molarities, if our solutions are standardized. A 0.196 g sample of a
kvv77 [185]

Answer:

The mass percent of Al(OH)₃ is 15.3%

Explanation:

The reaction is:

Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O

The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:

NaOH + HCl = NaCl + H₂O

The total moles of HCl is:

n_{HCl,total} =M_{HCl} *V_{HCl} =0.111*0.025=2.78x10^{-3} moles

From the second titration, the moles of excess of HCl is:

n_{HCl,excess} =n_{NaOH} =M_{NaOH} *V_{NaOH} =0.132*0.01105=1.46x10^{-3} moles

The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

n_{HCl,reacts} =n_{HCl,total}-n_{HCl,excess} =2.78x10^{-3} moles-1.46x10^{-3} moles=1.32x10^{-3} moles

The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:

m_{Al(OH)3} =1.32x10^{-3} molesHCl*\frac{1molAl(OH)3}{3molesHCl} *\frac{78gAl(OH)3}{1molAl(OH)3} =0.03g

The percentage of Al(OH)₃ is:

Percentage-Al(OH)3=\frac{m_{Al(OH)3} }{m_{antiacid} } *100=\frac{0.03}{0.196} =15.3%

3 0
3 years ago
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