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alexandr402 [8]
3 years ago
10

A substance has an empirical formula of CH2 and a molar mass of 56 grams per mole. The molecular formula for this compound is

Chemistry
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

The molecular formula for this compound is C4H8 (option A)

Explanation:

Step 1: Data given

Empirical formula of the compound is CH2

Molar mass of the compound is 56 g/mol

Step 2:

Since the empirical formula is CH2, this means we have 1 mol C for each 2 mol H

The molar mass of the empirical formula = 12 + 2*1 = 14 g/mol

To find the molecular formula we have to multiply the empirical formula by n.

n = molar mass of molecular formula / molar mass of empirical formula

n = 56 / 14

n = 4

Molecular formula = 4*(CH2) = C4H8

We can check this by calculating the molar mass of this formula

4*12 + 8*1 = 48+8 = 56 g/mol

The molecular formula for this compound is C4H8 (option A)

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The half oxidation-reduction reactions are:

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The balanced redox reaction will be:

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Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

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Now put all the given values in above equation, we get

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Therefore, the half-life of the compound is, 145 years.

8 0
4 years ago
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