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Valentin [98]
3 years ago
14

Please help will mark brainliest

Mathematics
1 answer:
TEA [102]3 years ago
6 0

we know that

total of sum of arc is 360

so, sum of both arc must be 360

so, we get

90+x=360

now, we can solve for x

90+x-90=360-90

x=270............Answer


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A baseball team wants to collect at least 160 cans of food for an upcoming food drive. Team members brought 42 cans of food on M
Irina18 [472]
If they collect 65 on Monday, 42 on Wednesday and the rest on Friday, then we can write it down as:

65 + 42 + x ≥ 160
107 + x ≥ 160                 / - 107 (both sides)
x ≥ 53

So the team needs to collect at least 53 cans on Friday.
4 0
3 years ago
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Find the volume of a right prism with height h=10 cm, if: a The base is equilateral triangle with side 4 cm, base altitude of ≈
Dvinal [7]
V=BA×h
A(triangle)=(4×3.5)/2=7cm²
V(prism)=7×10=70cm³

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(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa
mr Goodwill [35]

Answer:

a) \frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}

b) P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform Y\sim Unif(A,B). And the density function would be given by:

f(x) =\frac{1}{B-A} , A

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}

And we can find the probability desired like this:

P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)

And from the cumulative distribution function of X ficen by F(X)\frac{X-A}{B-A} we got:

\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}

Part b

For this case we assume that X\sim Gamma (2,1)

On this case we assume that \alpha=2, \beta= 1

The density function for the Gamma distribution is given by:

P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}

And on this case we can find the probability using the complement rule like this:

P(X>1) = 1-P(X\leq 1)=0.736

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736

6 0
3 years ago
Fred buys flags from a manufacturer for f dollars
Brilliant_brown [7]

Answer:0.26

How did i get that answer you ask?

i divide

6 0
3 years ago
Given that 1/(3^x) = 0.2<br> Find the value of (3^4)^x
bulgar [2K]
Hope this would help you

6 0
4 years ago
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