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Vaselesa [24]
3 years ago
7

A printing service charges a set-up fee of $12.50 for each order and 7 cents more for each copy. The total cost, C (in dollars),

for an order of x copies is given
by the following.
C =0.07x+12.50
What is the total cost for an order of 20 copies?
___ dollars
Mathematics
1 answer:
valentina_108 [34]3 years ago
7 0

Answer: the total cost for an order of 20 copies is $13.9

Step-by-step explanation:

Let x represent the number of copies ordered.

The printing service charges a set-up fee of $12.50 for each order and 7 cents more for each copy.

The equation representing the total cost, C (in dollars), for an order of x copies is expressed as

C = 0.07x + 12.50

Therefore, the total cost for an order of 20 copies would be

C = 0.07 × 20 + 12.5

C = 1.4 + 12.5

C = 13.9 dollars

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2 years ago
a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and
fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

x(t) = -4.9t^{2} + 9.8t

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format x(t) = at^{2} + bt + c

The vertex is the point (t_{v}, x(t_{v})), in which

t_{v} = -\frac{b}{2a}

In this question:

x(t) = -4.9t^{2} + 9.8t

So a = -4.9, b = 9.8

Vertex:

t_{v} = -\frac{9.8}{2*(-4.9)} = 1

The time taken for the upward motion is 1 second.

x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

-4.9t^{2} + 9.8t = 0

4.9t^{2} - 9.8t = 0

4.9t(t - 2) = 0

4.9t = 0

t = 0

Or

t - 2 = 0

t = 2

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

5 0
3 years ago
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