Question

Solve the equation using the method of completing the square. 2x^2+16x-8=0

Answer 1

Answer:

1) Move the "non X" term to the right:

2x^2+16x-8=0 becomes

2x^2 +16x = +8

2) Divide the equation by the coefficient of X² which in this case is 2

x^2 + 8x = 4

3) Now here's the "completing the square" stage in which we:

     • take the coefficient of X  (which is 8)

     • divide it by 2  [8 / 2 = 4]

     • square that number  [4^2 = 16]

     • then add it to both sides of the equation.

x^2 + 8x  + 16 = 20

Take the square root of both sides of the equation:

x + 4 = sq root (20)

x = sq root (20) -4

x1 = 4.472135955 -4

x1 = .472135955

x2 = -4.472135955 -4

x2 = -8.472135955

Source: https://www.1728.org/quadr2.htm

Step-by-step explanation: