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3 years ago

3(3b +2)=-30 what is b =

1 answer:

4 0

3(3b+2)=-30 perform indicated multiplication on left side...

9b+6=-30 subtract 6 from both sides

9b=-36 divide both sides by 9

b=-4

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Write a number as a cube 1/64

butalik [34]

Answer: Cube root of 64 in radical form: ∛64.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

For what values of b will F(x) = logbx be a decreasing function?

Anastasy [175]

Answer:

It is a decreasing function for 0 < b < 1.

Step-by-step explanation:

Logarithm function:

The logarithm function is given by:

$F(x) = \log_{b}{(x)}$

The base b determines if the function increases or decreases.

For 0 < b < 1, the function decreases.

For b > 1, the function increases.

In this question:

By the definition above, it is a decreasing function for 0 < b < 1.

3 0

3 years ago

Bob had 2 apples Sam took 1 how many is left

Brilliant_brown [7]

1 apple is left..
2-1=1

5 0

3 years ago

Solve the inequality –3(r – 5) + 7 > 28.

docker41 [41]

Answer: r<-2

Step-by-step explanation:

-3(r-5)+7>28

-3(r-5)+7-7>28-7

-3(r-5)>21

3(r-5)/3 < -21/3

r-5<-7

r-5+5<-7+5

r<-2

5 0

3 years ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0

3 years ago