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grigory [225]
2 years ago
12

Find the values of x and y that satisfy the equation.

Mathematics
1 answer:
HACTEHA [7]2 years ago
5 0

Answer:

x=-5-2yi/3+4i

y=3xi/2+6+15i/2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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If the measure of DEF is 65 what is the measure of DE. PLEASE HELP FAST
Wittaler [7]

EF is tangent to the circle we'll assume; otherwise there's no progress.


Call the center C. ECD is isosceles, formed from two radii and the chord.


Angle CED is complementary to DEF


CED = 90 - 65 = 25 degrees


CDE is congruent, isosceles triangle and all that: CDE=25


That leaves DCE=180-25-25=130 degrees


That's the measure of arc DE as well:


Answer: 130 degrees, choice A




8 0
3 years ago
Read 2 more answers
Dan had 2 1/2 cookies and ate 1/2 of a cookie. Of the original number of cookies, the fractional part that he ate was
Lemur [1.5K]

Answer:

1/2 is the fractional part of cookie which was eaten by Dan.

Step-by-step explanation:

Dan has 2 1/2 cookies and ate 1/2, so we can just subtract the 2 1/2-1/2

which cancels out the 1/2, which is the fractional part.

He has 2 cookies left.

5 0
3 years ago
HELP ASAP!!!!!!!!!!!!!
Mandarinka [93]
It will be 69 degrees.

(x-1)+x+43=180
2x+42=180
2x=138
x=69
4 0
3 years ago
25. The figure shows a pie chart drawn to show the amount of white, yellow and pink flowers in a
harina [27]

Answer:

zgtz yzuzibzibjahsyssgs

Step-by-step explanation:

svgzhzybzvtztczy xuvxyvxyvxyxvyxvyxvydvdvydyvdbudubdbudbudbudyvdu d udub

7 0
3 years ago
An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
2 years ago
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