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4 years ago

10

how are adding and subtracting two rational numbers with different signs related to adding and subtracting two integers with dif

ferent signs.

1 answer:

Nata [24]4 years ago

4 0

Answer:

Step-by-step explanation:

it is related as all integers are rational numbers

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Andy and Christopher are measuring a liquid solution using graduated cylinders, Andy uses 3.5 liters of the liquid solution, and

Gre4nikov [31]

Answer:

$Ratio = 0.74$

Step-by-step explanation:

Represent

- Andy with A

- Christopher with C

$A = 3.5L$

$C = 2580mL$

Required

Determine the ratio of C to A

Ratio is represented as thus:

$Ratio = C:A$

Rewrite as fraction

$Ratio = \frac{C}{A}$

This gives

$Ratio = \frac{2580mL}{3.5L}$

Convert L to mL

$Ratio = \frac{2580mL}{3.5*1000mL}$

$Ratio = \frac{2580mL}{3500mL}$

$Ratio = \frac{2580}{3500}$

$Ratio = 0.73714285714$

$Ratio = 0.74$ --- Approximated

6 0

3 years ago

Make x the subject of the formula a − bx = c

Eddi Din [679]

Answer:

x = c - a / -b

Step-by-step explanation:

a - bx = c

-a -a

-bx = c - a

divide -b

x = c - a / -b

3 0

3 years ago

Read 2 more answers

Which of the following equations will produce the graph shown?

Artemon [7]

Try this option (it is not the only way):
the points (0;0) and (2;2) belong to the curve. Using the coordinates of these points it is possible to calculate the equation.
$y= \frac{1}{2}x^2;$

5 0

3 years ago

Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2

Leviafan [203]

we are given

$r(t)=(7t,3cos(t),3sin(t))$

we can find x , y and z

$x=7t,y=3cos(t),z=3sin(t))$

now, we can use arc length formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

now, we can find derivative

$x'=7,y'=-3sin(t),z'=3cos(t))$

now, we can plug values

and we get

$L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt$

$L=\int _{-2}^2\sqrt{7^2+9}dt$

$=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)$

$L=4\sqrt{58}$ ...........Answer

8 0

3 years ago

A teacher is four time as old as a student .in 20 years, the student 's age will be half of the teacher 's age. How old are they

notka56 [123]

Let the present age of student be x
Present of teacher will be 4x

After 20 years,
Age of student = x + 20
Age of teacher = 4x + 20

According to the given condition after 20 years,
x + 20 = (4x + 20)/2
x + 20 = 2x + 10
2x - x = 20 - 10
x = 10

So student's present age is 10 years while teacher's is 4 x 10 i.e 40 years.

Hope This Helps You!

5 0

4 years ago