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const2013 [10]
2 years ago
5

Find Dept equity ratio and total assets is equal to 160000 and total debt= 80000 and current liabilities= 20000

Mathematics
1 answer:
rewona [7]2 years ago
4 0

Answer:

bobo taran ta do pitang ina mo ka

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Use substitution to solve the<br> following system of equations.<br> 2x + 4y = 12 AND x=y - 3
Kamila [148]

Answer:

The solution is (0, 3)

Step-by-step explanation:

First, reduce 2x + 4y = 12 to x + 2y = 6, for easier calculations.

Next, substitute y - 3 for x in the other equation:

y - 3 + 2y = 6, or

3y = 9

Then y = 3.  Since x = y - 3 in general, x = 3 - 3 = 0 when y = 3.

The solution is (0, 3)

8 0
3 years ago
The senior classes at Snellville High and General High planned separate trips to the water park. The senior class at Snellville
Aleonysh [2.5K]

Answer:

133

Step-by-step explanation:

Snellville

12v+14b = 796

General

14v+12b =738

We need to solve for v and b where v is how many on a van and b is how many on a bus

12v+14b = 796

14v+12b =738

Divide each equation by 2

6v+7b =398

7v+6b =369

Multiply the first equation by 7 and the second equation by -6

7(6v+7b) =7(398)  

42v +49b =2786

-6(7v+6b) =369*-6

-42v -36b = -2214

Add these equations together

42v +49b =2786

-42v -36b = -2214

-------------------------------

     13b = 572

Divide each side by 13

13b/13 = 572/13

b= 44

Now find v

6v+7b =398

6v +7(44)=398

6v +308 = 398

Subtract 308 from each side

6v = 90

Divide by 6

6v/6 = 90/6

v = 15

We want 2 b and 3 v

2b+3v = 2(44)+3(15) = 88+45=133

5 0
2 years ago
Read 2 more answers
A closed container has 6.08 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams. Which of the following shows
Firdavs [7]
To calculate for the total mass of the atoms of gas in the container, we simply multiply the number of atoms and the mass of each.
                total mass = (6.08 x10²³ atoms) x (1.67 x 10⁻²⁴ grams/ atom)
                   total mass = 1.015 grams

Therefore, the answer is the first choice. 
3 0
3 years ago
Find the difference: (-3.4x+4.7)-(3+2.9x)
Ostrovityanka [42]

Answer:

-6.3x + 1.7

Step-by-step explanation:

(-3.4x +4.7) - (3 +2.9x)

distrubute the negitive sign

-3.4 +4.7 -3 -2.9x

combine like terms

-6.3x + 4.7-3

-6.3x +1.7

4 0
3 years ago
To lift a load of 100 n a distance of 1 m an effort of 25 n must be applied over an inclined plane of length 4 m. What must be d
aleksklad [387]

An inclined plane of length 8 m is used to lift the load 2 m, using the same effort.

A ramp that helps lift and lower heavy things is called an inclined plane. It is a flat surface that is positioned against a horizontal surface at an angle other than a right angle.

Work is defined as the use of force to move an object over a distance. It is derived as the product of displacement (d) and force (F). Work is given by W = F×d = 25 N×d.

When a body is lifted, we can express work as W = m×g×h where g is gravity and h is height. And the force is written as F = m×g where m is the mass of an object. Then, W = F×h

Calculating the work done to lift the load to 2 m, we get,

W = 100 N×2 m = 200 Nm.

Substitute this value in W = F×h, we get,

200 Nm = 25 N×d

Divide both sides by 25 N, and we get,

\begin{aligned}\frac{\mathrm{200\;Nm}}{\mathrm{25\;N}}&=\frac{\mathrm{25\;N\times d}}{\mathrm{25\;N}}\\d&=\mathrm{8\;m}\end{aligned}

The value is 8 m. Therefore, the first statement is correct.

The complete question is -

To lift a load of 100 N a distance of 1 m an effort of 25 N must be applied over an inclined plane of length 4 m. What must be done to lift the load 2 m, using the same effort?

A. Use an inclined plane of length 8 m.

B. Use an inclined plane of length 2 m.

C. Use an inclined plane of length 10 m

D. Use an inclined plane of length 16 m.

To know more about work:

brainly.com/question/2005605

#SPJ4

7 0
1 year ago
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