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Alexxandr [17]
4 years ago
7

Can someone please solve 24 + 3x ≥ 100.

Mathematics
1 answer:
masha68 [24]4 years ago
7 0
24+3x <span>≥ 100
-24               -24

3x </span><span>≥ 76
</span>÷3    <span>÷3
</span><span>
x = 25.3

</span>
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Simplify the rational expression. State any restrictions on the variable.
ExtremeBDS [4]

we are given

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}

Firstly, we will factor numerators and denominators

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}

we can see that

n^2 -6 is factor on both numerator and denominator

so, it will get cancelled

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so, one of restriction is

n^2-6\neq 0

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we can simplify it

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-4)}{(n^2-3)}

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3 0
3 years ago
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