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liberstina [14]
3 years ago
15

Use Inverse operations to solve the expression. Enter your answer in simplest form. y 1 =8 16​

Mathematics
1 answer:
vredina [299]3 years ago
7 0
So we are trying to get the “y” alone, so to undo the division by -8, we will multiply both sides by -8, then simplify.

(-8) y/(-8) = (-8) 1/16

y = -8/16

and simplified:

y = -1/2
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Fiesta28 [93]

Answer:

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Part 2) 215km in 25s --> Does not have the same speed as  Saige's spaceship

Part 3) 649km in 110s --> Does not have the same speed as  Saige's spaceship

Step-by-step explanation:

<u><em>The complete question is</em></u>

Saige's spaceship traveled 588 kilometers in 60 seconds.

Determine whether or not each spaceship trip below has the same speed as Saige's spaceship.

441km in 45s

215km in 25s

649km in 110s

we know that

The speed is equal to divide the total distance traveled by the total time

In this problem we have that

The speed of Saiges spaceship is equal to

\frac{588}{60}=9.8\ \frac{km}{sec}

case 1) we have

441km in 45s

Find out the speed of the  spaceship trip

\frac{441}{45}=9.8\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

9.8\ \frac{km}{sec}=9.8\ \frac{km}{sec}

therefore

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case 2) we have

215km in 25

s

Find out the speed of the  spaceship trip

\frac{215}{25}=8.6\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

8.6\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}

therefore

Does not have the same speed as  Saige's spaceship

case 3) we have

649km in 110s

Find out the speed of the  spaceship trip

\frac{649}{110}=5.9\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

5.9\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}

therefore

Does not have the same speed as  Saige's spaceship

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