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nata0808 [166]
3 years ago
8

What is the difference of the fractions?​

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

11/20

Step-by-step explanation:

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Pam needs 3 1/2 cups of sugar to make 50 cupcakes, a 5-pound bag of sugar costs $3.69. There are about 2 cups of sugar in a poun
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$1.70

Step-by-step explanation:

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The length of the United States flag is 1 9/10 times the width of the flag. A particular U.S. flag is 5 feet long. Write and sol
elena-14-01-66 [18.8K]

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2 12/19

Step-by-step explanation:

7 0
3 years ago
Let p, q, and r represent the following statements"
-BARSIC- [3]

Answer:

Step-by-step explanation:

$$a. Sam had pizza last night and Chris finished her homework.\\p\wedge q\\\\$b. Chris did not finish her homework and Pat watched the news this morning.$\\\neg q \wedge r\\\\$c. Sam did not have pizza last night or Chris did not finish her homework.$\\\neg p \vee \neg q\\\\

$$d. Either Chris finished her homework or Pat watched the news this morning, but not both.$\\q\vee r\\\\$e. If Sam had pizza last night then Chris finished her homework.$\\p \rightarrow q\\\\$f. Pat watched the news this morning only if Sam had pizza last night.$\\p\leftrightarrow r\\\\

$$g. Chris finished her homework if Sam did not have pizza last night.$\\\neg p \rightarrow q\\\\$h. It is not the case that if Sam had pizza last night, then Pat watched the news this morning.$\\\neg (p\rightarrow r)\\\\

$$i. Sam did not have pizza last night and Chris finished her homework implies that Pat watched the news this morning.$\\(\neg p \wedge q) \Rightarrow r\\\\ $j. q\Rightarrow r$\\Chris finished her homework implies that Pat watched the news this morning.\\\\

$$k. p \Rightarrow (q \wedge r)$\\Sam has pizza last night implies that Chris finished her homework and Pat watched the news this morning.$\\\\

$$l. \neg p \Rightarrow (q \vee r)$\\Sam did not have pizza last night implies that Chris finished her homework or Pat watched the news this morning.$\\\\

$$m. r \Rightarrow (p \vee q)$\\Pat watched the news this morning implies that Sam had pizza last night or Chris finished her homework$

3 0
3 years ago
A2. Find y' and y" for y^2 = x^2<br>+ sinxy
kumpel [21]

Answer:

y'   = (2x + y cosxy)/(2y + x cosxy)

Step-by-step explanation:

Using implicit differentiation:

y^2 = x^2 + sin xy

2y y' = 2x + cos xy  * (xy' + y)

2y y' = 2x + xy' cos xy + y cos xy

2y y' - xy' cosxy = 2x + ycos xy

y'   = (2x + y cosxy)/(2y - x cosxy)

4 0
3 years ago
Help me plz this is to much
mr Goodwill [35]

9514 1404 393

Answer:

  • 1 triangle: 2 m²
  • 2 triangles: 4 m²
  • large rectangle: 32 m²
  • small rectangle: 3 m²
  • total area: 39 m²
  • cost of tile: $487.50

Step-by-step explanation:

You will run across many examples of poorly edited curriculum materials. This is one of them. We presume that every instance of "inches" should be an instance of "meters". The difference between in and m is not always obvious in a diagram, and m apparently got misinterpreted here.

__

The area of a triangle is given by the formula ...

  A = 1/2bh

where b is the base and h is the height perpendicular to the base.

The triangles in this figure have a base of 4 m, and a height of 1 m. Using this formula, we find the area of 1 triangle to be ...

  A = 1/2(4 m)(1 m) = 2 square meters . . . . area of 1 triangle

__

The triangles are the same size, so the area of both together is ...

  2(2 m²) = 4 square meters . . . . area of both triangles together

__

The large rectangle is 8 m long and 4 m high. Its area is given by the formula ...

  A = LW

where the length is L and the width is W. Using this formula, we find the area of the large rectangle to be ...

  A = (8 m)(4 m) = 32 m² . . . . area of large rectangle

__

The small rectangle has a length of 3 m and a width of 1 m. Its area is ...

  A = (3 m)(1 m) = 3 m² . . . . area of small rectangle

__

The total area is the sum of the areas of the pieces:

  total area = 2 triangles + large rectangle + small rectangle

  total area = 4 m² + 32 m² + 3 m² = 39 square meters

_____

At $12.50 per square meter, the cost of covering the patio is ...

  ($12.50/m²)(39 m²) = $487.50 . . . . cost of tile

5 0
3 years ago
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