6 1/12 would be the answer
Rewriting our equation with parts separated
1/3+5+3/4
Solving the fraction parts
1/3+3/4=?
Find the LCD of 1/3 and 3/4 and rewrite to solve with the equivalent fractions.
LCD = 12
4/12+9/12=13/12
Simplifying the fraction part, 13/12,
13/12=11/12
Combining the whole and fraction parts
5+1+1/12=6 1/12
What you would do is multiply 72 and 3 so it says three times so you multiply 72 three times so this would equal 638
The formula to find the Height of a triangle when you have the Area and the base is H = 2 * A/b
if the Area is 36.8 then divide it by 4.6. You get 8. put 36.8 in calculator first, then 4.6 = 8
2 x 8 = 16...so the answer should be 16 inches.
2 is in the formula to multiply to the number you get after dividing the base into the Area.
16 Answer
Answer:
82
Step-by-step explanation:
180+148+xy=360
xy=32
arc=32=double the angle=16 degrees
Since both are radii they are equal. It is an isoceles triangle so angle x equals angle y.
180=16=164/2=82
Answer:
1963.2 pounds (lbs.)
Step-by-step explanation:
Things to understand before solving:
- - <u>Normal Probability Distribution</u>
- The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by:

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.
- - <u>Central Limit Theorem</u>
- The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц and standard deviation

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.
This means, ц = 2000 and б = 100.
A random sample of 20 cables is chosen and tested.
This means that n = 20, 
Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.
This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So 
- By the Central Limit Theorem


<h3>Answer:</h3>
The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.