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VARVARA [1.3K]
2 years ago
6

Seven increased by the product of two numbers Seven increased by the product of two numbers

Mathematics
1 answer:
Crazy boy [7]2 years ago
4 0

Whats the two numbers?


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PLS HELP! WILL GIVE BRAINLIEST
Zepler [3.9K]

Answer: do 2.1 times 100 than that answer times 0.6

Step-by-step explanation:

3 0
3 years ago
In an aquarium, there are 10 large fish and 5 small fish. Half of the large fish are red.
vfiekz [6]

Answer:

There's 21% of chances

Step-by-step explanation:

Here we have to use the definition of a simple probability, where all fishes has the same probability to be chose.

So, we have to divide the possible outcomes with the total of outcomes. The possible outcomes refer to the number of large-blue fishes, and the total number of outcomes represent the total number of fishes. So

P = 3/4 ≈ 0.21 (or 21%)

Therfore, there's 21% of chances to select one fish randomly and be a large, blue fish.

3 0
3 years ago
Read 2 more answers
Z +6 divided by 1/3 = 4
Allushta [10]

Hey there!!

z + 6 / 1/3 = 4

z + 6 = 4 × 1/3

z + 6 = 4/3

z = 4/3 - 6

z = 4 - 18 / 3

z = -14/3

Hope it helps!

7 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
What is the sum of two numbers a and b decreased by their product?
belka [17]

The sum of two numbers a and b decreased by their product is (a+b)-ab

Step-by-step explanation:

Given the two numbers as a and b

Sum of these two numbers is a+b

The product of the two numbers is a*b, ab

The sum of the two numbers decreased by their product will be;

(a+b)-ab

Learn More

  • https://brainly.in/question/6082654
  • https://brainly.in/question/6940394

Keywords : sum of two numbers, product

#LearnwithBrainly

8 0
3 years ago
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