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den301095 [7]
3 years ago
12

SOMEONE HELP I DONT KNOW WHAT THE HECK IM DOING (7th grade)

Mathematics
2 answers:
m_a_m_a [10]3 years ago
7 0

Answer:

Step-by-step explanation:

I'm 8th grade, G

For this problem, you can start by taking the 35 and dividing it by 5 to get 7. Then you need to take 300 and divide that by 5 to get the right proportions. Then you can take your new number from 300 and divide that by 7, and you should not be on the right path because I'm probably an idiot.

Sorry bout it

Dmitry [639]3 years ago
6 0

Answer:

hi

Step-by-step explanation:

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3 years ago
Which of the following is a polynomial?
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2 and the 4 needs to add subtract too much
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How resolve it<br>plssss​
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Step-by-step explanation:

6 0
3 years ago
The vertices of APQR are P(-3, 8) Q(-6,-4), and R(1, 1). If you reflect APQR across the x-axis, what will be the coordinates of
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Answer:(-3,-8),(-6,4),(1,-1)

Step-by-step explanation:

Given

Vertices of the triangle are

P(-3,8), Q(-6,-4),R(1,1)

Coordinates (a,b) when reflected about x-axis is given as (a,-b) i.e. Y coordinate changes its sign

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4 0
3 years ago
Reflect the given preimage over y=−1 followed by y=−7. Find the new coordinates. What one transformation is this double reflecti
fenix001 [56]

Answer:

Reflecting over y = -1 line:

A'(8, -10)

B'(10, -8)

C'(2, -4)

Reflecting over y = -7 line:

A''(8, -4)

B'(10, -6)

C''(2, -10)

Step-by-step explanation:

Reflect the given preimage over y=−1 followed

by y=−7. Find the new coordinates. What one transformation is this double reflection the same as? (Note: when you are reflecting over a y= line, the x-values of the preimage will remain the same and you will be changing the y-values)

The coordinates of the preimage are:

A(8,8)

B(10,6)

C(2,2)

Answer: Reflecting over y = -1:

If a point is reflected over a y line, the x values remain the same while the y values change.

For point A(8, 8): The y distance between the y = - 1 line and point A is 9 units. (8- (-1)). If point A is reflected, the y value would be 9 units below the y = -1 line, i.e the new y coordinate would be at -10 (-1-9)

The new coordinate is at A'(8, -10)

For point B(10, 6): The y distance between the y = - 1 line and point B is 7 units. (6- (-1)). If point B is reflected, the y value would be 7 units below the y = -1 line, i.e the new y coordinate would be at -8 (-1-7)

The new coordinate is at B'(10, -8)

For point C(2, 2): The y distance between the y = - 1 line and point C is 3 units. (2- (-1)). If point C is reflected, the y value would be 3 units below the y = -1 line, i.e the new y coordinate would be at -4 (-1-3)

The new coordinate is at C'(2, -4)

Reflecting over y = -7 line:

For point A'(8, -10): The y distance between the y = - 7 line and point A' is 3 units. (-7- (-10)). If point A' is reflected, the y value would be 3 units above the y = -7 line, i.e the new y coordinate would be at -4 (-7+3)

The new coordinate is at A''(8, -4)

For point B'(10, -8): The y distance between the y = - 7 line and point B' is 1 units. (-7- (-8)). If point B' is reflected, the y value would be 1 units above the y = -7 line, i.e the new y coordinate would be at -6 (-7 + 1)

The new coordinate is at B'(10, -6)

For point C'(2, -4): The y distance between the y = - 7 line and point C' is 3 units. (-4- (-7)). If point C' is reflected, the y value would be 3 units below the y = -7 line, i.e the new y coordinate would be at -10 (-7-3)

The new coordinate is at C''(2, -10)

We can also see that h= −7−(−1)=−6. We know that two reflections is the same as a translation of 2h  units down. So 2(−6) is a translation of −12 units down.

5 0
3 years ago
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