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amm1812
3 years ago
10

In an aquarium, there are 10 large fish and 5 small fish. Half of the large fish are red.

Mathematics
2 answers:
vfiekz [6]3 years ago
3 0

Answer:

There's 21% of chances

Step-by-step explanation:

Here we have to use the definition of a simple probability, where all fishes has the same probability to be chose.

So, we have to divide the possible outcomes with the total of outcomes. The possible outcomes refer to the number of large-blue fishes, and the total number of outcomes represent the total number of fishes. So

P = 3/4 ≈ 0.21 (or 21%)

Therfore, there's 21% of chances to select one fish randomly and be a large, blue fish.

andrey2020 [161]3 years ago
3 0

Answer:

30%

Step-by-step explanation

There are 15 fish in total, using that we can say the probability of picking a large fish at random is about 30% or 1/3 of the fish.

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<h2><u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>

Given system of linear equations are ,

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And we need to find the Solution of the linear equation . So let's Firstly number the equations .

\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}

<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

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<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

<h3><u>★</u><u> </u><u>Hence</u><u> the required solution is ( 0 , 2 ) .</u></h3>
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