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amm1812
3 years ago
10

In an aquarium, there are 10 large fish and 5 small fish. Half of the large fish are red.

Mathematics
2 answers:
vfiekz [6]3 years ago
3 0

Answer:

There's 21% of chances

Step-by-step explanation:

Here we have to use the definition of a simple probability, where all fishes has the same probability to be chose.

So, we have to divide the possible outcomes with the total of outcomes. The possible outcomes refer to the number of large-blue fishes, and the total number of outcomes represent the total number of fishes. So

P = 3/4 ≈ 0.21 (or 21%)

Therfore, there's 21% of chances to select one fish randomly and be a large, blue fish.

andrey2020 [161]3 years ago
3 0

Answer:

30%

Step-by-step explanation

There are 15 fish in total, using that we can say the probability of picking a large fish at random is about 30% or 1/3 of the fish.

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Find the equation of the exponential function represented by the table below
Gennadij [26K]

Answer:

y = 3^(1 + x)

Step-by-step explanation:

Notice that each time x increases by 1, y increases by a factor of 3.

Thus, the required equation  has the form y = 3^x.

Check:  If x = 0, do we get 3?  No.  Therefore we must modify the exponent:

y = 3^(1 + x)

Check:  If x = 0, do we get 3?  3^(1 + 0) = 3 (correct)

If x = 2, do we get 27?  3(1 + 2) = 3^3 + 27 (correct)

4 0
3 years ago
What is the vertex of function f(x)=(x-3)(x+5)?
butalik [34]

Answer:

( − 1 , − 16 )

Step-by-step explanation:

6 0
3 years ago
Please use an equation step by step and please show the numbers do not use words
Pepsi [2]

Answer:

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3 0
2 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
What is 8 meters increased by 25 percent
Lorico [155]
25% is 1/4 so you do 8 times 1/4 and that's 2.
8 0
3 years ago
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