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3 years ago

13

Which ordered pair is a solution of the system of equations?

1 answer:

levacccp [35]3 years ago

3 0

{y=3x+1 |*5
{y=5x-3 |*(-3)

{5y=15x+5
{-3y=-15x+9
+___________
2y=14

{y=7
{7=3x+1

{3x=6
{y=7

{x=2
{y=7

The answer: C

:)

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Line segment AB is dilated to create line segment A'B' using point Q as the center of dilation.

Rashid [163]

Answer:

2

Step-by-step explanation:

To find the scale of dilation, you have to compare the ratio of the after transform with before transform according to the center of dilation. In this case, the center of dilation is Q so you have to compare QA' : QA. We know that QA= 1.25 and AA' is 1.25. The distance of QA' will be:

QA'= QA + AA'= 1.25 + 1.25 = 2.5

The scale factor will be:

scale factor= QA' : QA.= 2.5 : 1.25

scale factor= 2

7 0

3 years ago

Read 2 more answers

Solve the equation -9v-9=-27 for v.

Nikolay [14]

Answer:

v=2

Step-by-step explanation:

-9v-9=-27

add nine to both sides

-9v-9+9=-27+9

simplify

-9v=-18

divide both sides by -9

-9v/-9 -18/-9

simplify y=2

hope this helps :) have a nice day !!

4 0

3 years ago

Read 2 more answers

Plzzzz help mehh its scientific notation and im putting alot o point for it

s344n2d4d5 [400]

$(7.2\cdot10^7)^2=7.2^2\cdot(10^7)^2=51.84\cdot10^{14}=\boxed{5.184\cdot10^{15}}=\\
\boxed{5,184,000,000,000,000}$

5 0

3 years ago

What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

Read 2 more answers

8. Sam divided a rectangle into 8 congruent

S_A_V [24]

Sam divided a rectangle into 8 congruent rectangles that each have a area of 5 cm2. what is the area of the rectangle before it is divided?

Answer:

$Area\ of\ the\ rectangle = 40\ cm^{2}$

Step-by-step explanation:

Given:

Sam divided a rectangle into 8 congruent rectangles that each have an area of $5\ cm^{2}$

We need to find the area of the rectangle before Sam divided it.

The area of the rectangle before Sam divided is 8 times of the area of the congruent rectangles.

Area of the rectangle = $8\times (area\ of\ congruent\ rectangles)$

Area of the congruent rectangle is $5\ cm^{2}$

So the area of the rectangle is

Area of the rectangle = $8\times 5$

Area of the rectangle = $40\ cm^{2}$

Therefore the area of the rectangle before divided is $40\ cm^{2}$

4 0

2 years ago