Answer:
Hi there!
Recall that slope-intercept form is:
y = mx + b
Where m = slope
In this instance, we are given a slope of 4,
therefore:
y = 4x + b
Substitute in the x and y coordinates of the point given:
0 = 4(3) + b
0 = 12 + b
Substract 12 from both side:
-12 = b
Therefore, the equation would be:
y = 4x - 12
Graph the equation by finding x and y values or using a calculator:
x = 0, y = 4(0) - 12 = 12 (0, 12)
x = 1, y = 4(1) - 12 = - 8 (1, -8)
x = 2, y = 4(2) - 12 = - 4 (2, -4)
x = 3, y = 4(3) - 12 = 0 (3, 0)
And so forth:
Thanks<8
you can either subtract 6-(-3) or do a number line -3, -2, -1, 0, 1, 2, 3, 4, 5, 6
count up from -3, and you'll get 9, same as subtracting 6 from -3. answer is 9 degrees F
Answer:
P( yellow) = 8/23
P( blue or green) = 9/23
P(orange) = 0
Step-by-step explanation:
6 red, 5 green, 4 blue, and 8 yellow M&M's = 23 total
P( yellow) = yellow / total = 8/23
P( blue or green) = (blue+green) / total = (5+4)/23 = 9/23
P(orange) = orange/ total = 0/23
Answer:
nahh I'm good thanks for points tho
Answer:
Step-by-step explanation:
SecA - TanA
= 1/CosA - SinA/CosA
= 1 - SinA/CosA
We know that Sin2A = 2SinACosA and Cos2A = Cos²A - Sin²A
Thus SinA = Sin2(A/2) = 2Sin(A/2)CosA/2
CosA = Cos2(A/2) = Cos²A/2 - Sin²A/2
Now substituting the values back,
=> 1 - 2Sin(A/2)Cos(A/2) / Cos²(A/2) - Sin²(A/2)
// we know that Sin²θ + Cos²θ = 1
=> Sin²(A/2) + Cos²A/2 - 2Sin(A/2)Cos(A/2) / Cos²(A/2) - Sin²(A/2)
//We know that numerator is of form a² + b² - 2ab which is (a - b)².
//Similarly denominator is of form a² - b² which is (a - b)(a + b)
=> [Sin(A/2) - Cos(A/2)]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [ - {Cos(A/2) - Sin(A/2)}]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [Cos(A/2) - Sin(A/2)]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [Cos(A/2) - Sin(A/2)] / [Cos(A/2) + Sin(A/2)]
= R.H.S
Hence proved.
