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Furkat [3]
3 years ago
9

What three distinct elements make up the cytoskeleton in eukaryotic cells?

Biology
1 answer:
natita [175]3 years ago
8 0

Answer:

Microfilaments, Intermediate filaments and microtubules

Explanation:

Three distinct elements make up the cytoskeleton in eukaryotic cells are:

1. Microfilaments or actin filaments which are composed of actin proteins. The functions of those filaments are: muscle contraction (myosin heads move “walk” on actin filaments), the movement of the cell,  intracellular transport, maintaince of the cell shape..

2. Intermediate filaments which can be made of vimentins, keratin, lamin, desmin… Their functions are: the maintenance of cell shape, anchoring organelles, structural components of the nuclear lamina, cell-cell and cell-matrix junctions…

3. Microtubules are filaments polymers of alpha and beta tubulin. Their roles are in intracellular transport (associated with motor protein dyneins and kinesins),  formation of the axoneme of cilia and flagella, formation of the mitotic spindle.

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A protein has a molecular mass of 400 kDa when measured by gel filtration. When subjected to gel electrophoresis in the presence
RoseWind [281]

Answer:

subunit composition

  • how many: 4 subunits
  • what sizes: 160 kDa, 60 kDa, 90 kDa, and 90 kDa.

Explanation:

SDS is a detergent that denaturalizes the protein and sets a relation charge size, such as that the motion of the protein in the gel is proportional to its weight. However, <u>the detergent can not disrupt disulfide bridges, so these bonds remain together</u>. The bigger the protein is, the stronger interaction with the polyacrylamide gel there will be. The speed of displacement in the electromagnetic field is inversely proportional to the protein size.

 On the other hand, b-mercaptoethanol acts as a reductive agent, <u>breaking disulfide bonds</u>. This chemical produces a complete denaturalization resulting in the unfolded protein.<u> If disulfide bridges kept two protein subunits together, the b-mercaptoethanol separates them</u>.

So, the <em>most important data we need to consider here is that SDS can not disrupt disulfide bridges, while b-mercaptoethanol can</em>.

<u>Available data:</u>

  • A protein has a molecular mass of 400 kDa
  • SDS → three bands with molecular masses of 180, 160, and 60 kDa
  • SDS + b-mercaptoethanol → three bands with molecular masses of 160, 90, and 60 kDa

<u>SDS</u>

180 + 160 + 60 = 400 kDa

<u>SDS + b-mercaptoethanol</u>

160 + 90 + 60 = 310 kDa

The difference between them is 400 - 310 = 90 kDa, meaning that there is a subunit of 90 kDa that is not being detected by SDS alone.

From both measures ( SDS and SDS/b-mercaptoethanol) we can assume that subunits 160 kDa and 90kDa are the same. So the difference is in the left subunit ⇒ 180 and 90, respectively.

180 - 90 = 90 kDa

We can assume that the 180 kDa subunit is composed of two 90 kDa subunits joined by a disulfide bridge. SDS alone could not disrupt this bond, so it detected a unit of 180kDa. b-mercaptoethanol detected this bond and broke it, generating two 90 kDa units, which migrated together in the gel, so they were expressed as the same band.

This difference suggests that the protein is formed of 4 subunits. One of them is 160 kDa, another one is 90 kDa, and the last two subunits are 90 kDa each.

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