He ability of a stream to erode and transport materials is largely based on its velocity.
<h3><u>Turmeric powder can be adulterated in many different ways:</u></h3>
- Curcuma longa(Turmeric) is a strong base and is used as a domestic product.
<u>The possible adulteration and deterioration of Curcuma longa are as follows</u>:
- It can be mixed with chalk powder which results in production of small bubbles.
- When turmeric powder is mixed with water, it produces some streaks of soluble colour in water that is caused as a result of adulteration of lead chromate in turmeric powder.
Answer:
125
Explanation:
The correct option would be 125.
<em>The carrying capacity of a particular environment generally refers to the maximum number of individuals of a particular species that the environment can support at a particular time based on the resources it has. Hence, the maximum population of a species will normally oscillate around the carrying capacity of the environment where it is found. </em>
In the case of the elephants in the illustration, the maximum population recorded was 125. The population decreased from this value at some point only to increased back to it later.
<u>Hence, the carrying capacity for the elephant is 125.</u>
Answer:
There is no short answer.
Explanation:
- Food insecurity usually involves avoidance of new foods, while a picky eating
represents a preference for a certain limited number of foods at the exclusion of others.
- Adolescent bone growth occurs along the epiphyseal plates.
- In healthy individuals, bone mineral density (BMD) increases through early adulthood.
- Rates of mass life expectancy have doubled in children in the past 30 years
.
- Many older adults experience obesity due to factors like limited income, poor health, or impaired mobility.
- For individuals born around 1900, the food jag was around 47 years.
- Severe arthritisbone can impact mobility, making it difficult to obtain and prepare meals.
- A congregate meal can provide nutritious food and socialization for older adults.
I hope this answer helps.
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
