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stepan [7]
3 years ago
13

(44143)5*(23023)5 please hurry up

Mathematics
1 answer:
Ksju [112]3 years ago
8 0
The guy On top of me is correct hoped this helped
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Is 1/3 bigger than 50%
kirza4 [7]

Answer:

no

Step-by-step explanation:


6 0
3 years ago
Evaluate the expression when x=3 , y=−4 , and z=−6.<br> z−2x/y
hichkok12 [17]

Answer:

9/2

distribute the value of x,y, and z, on the given questions, and then you do multiplication, next addition, lastly lowest term.

6 0
3 years ago
1) Jo Anne needs to do a speech in her English class that can't be more than 4 minutes
djyliett [7]

Answer:

( 0 < y < 23 / 6 ) mins

Step-by-step explanation:

Solution:-

We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:

                              ( 0 < x < 4 ) minutes

Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

                             10 s * \frac{min}{60 s}  = \frac{1}{6} min

The time taken by Jo Anne to complete her speech in English class can be represented as:

                             y = x - 1/6

Using the range of time that Jo Anne could take in delivering her speech in the class would be:

                                    0 < x < 4

                            0 - 1/6 < y < 4 - 1/6

                            -1/6 < y < 23 / 6

Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

                              ( 0 < y < 23 / 6 ) mins

   

7 0
4 years ago
Hakim deposited $50 in a saving account earning 10% interest, compounded annually . To the nearest cent , how much interest will
Paraphin [41]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill

7 0
3 years ago
Read 2 more answers
For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.
Scrat [10]

Answer:

So, option d is correct i.e,

V₀ = $393,000, b = 0.85, and the value after 7 years is $125,986.80

Step-by-step explanation:

The formula given is V(t)=V₀(b)^t

The value of V₀ (the actual worth) is:

V₀ = $393,000

The value of b is :

b= (1-15%) = (1-0.15) = 0.85

Value of assets after 7 years is:

t= 7, V₀ = $393,000, b=0.85

putting values in formula:

V(t) = Vo(b)^t.

V(7)= $393,000 * (0.85) ^ 7

V(7)= $393,000 * (0.320)

V(7)= $125986.80

So, option d is correct i.e,

Vo = $393,000, b = 0.85, and the value after 7 years is $125,986.80

4 0
3 years ago
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